05_InstSolManual_PDF_Part1

05_InstSolManual_PDF_Part1 - APPLICATIONS OF NEWTON’S...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: APPLICATIONS OF NEWTON’S LAWS 5 9. A 10. C 11. C 12. B 13. D Answers to Multiple-Choice Problems 1. A 2. D 3. B 4. D 5. A 6. A 7. A 8. B Solutions to Problems 5.1. Set Up: Constant speed means a 5 0. Use coordinates where 1y is upward. The breaking strength for the rope in each part is (a) 50 N, (b) 4000 N, and (c) 6 3 104 N. The free-body diagram for the bucket plus its contents is given in Figure 5.1. y T a50 x w Figure 5.1 Solve: g Fy 5 may gives T 2 w 5 0 so T 5 w. (a) w 5 50 N, so 35 N of cement. The mass of cement is 3.6 kg. (b) w 5 4000 N, so 3985 N of cement. The mass of cement is 410 kg. (c) w 5 6 3 104 N, so 6 3 104 N of cement. The mass of cement is 6 3 103 kg. Reflect: Since a 5 0, the upward pull of the rope equals the total weight of the object. 5.2. Set Up: Use coordinates where 1y is upward. ay 5 0 for each object. Call the tension in the wires Tt (top), Tm (middle), and Tb (bottom). The free-body diagram for each object is given in Figure 5.2. y y y Tt Tm Tb a50 x a50 x W W W Tb Tm a50 x Figure 5.2 5-1 ...
View Full Document

Ask a homework question - tutors are online