05_InstSolManual_PDF_Part1 - APPLICATIONS OF NEWTON’S...

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Unformatted text preview: APPLICATIONS OF NEWTON’S LAWS 5 9. A 10. C 11. C 12. B 13. D Answers to Multiple-Choice Problems 1. A 2. D 3. B 4. D 5. A 6. A 7. A 8. B Solutions to Problems 5.1. Set Up: Constant speed means a 5 0. Use coordinates where 1y is upward. The breaking strength for the rope in each part is (a) 50 N, (b) 4000 N, and (c) 6 3 104 N. The free-body diagram for the bucket plus its contents is given in Figure 5.1. y T a50 x w Figure 5.1 Solve: g Fy 5 may gives T 2 w 5 0 so T 5 w. (a) w 5 50 N, so 35 N of cement. The mass of cement is 3.6 kg. (b) w 5 4000 N, so 3985 N of cement. The mass of cement is 410 kg. (c) w 5 6 3 104 N, so 6 3 104 N of cement. The mass of cement is 6 3 103 kg. Reflect: Since a 5 0, the upward pull of the rope equals the total weight of the object. 5.2. Set Up: Use coordinates where 1y is upward. ay 5 0 for each object. Call the tension in the wires Tt (top), Tm (middle), and Tb (bottom). The free-body diagram for each object is given in Figure 5.2. y y y Tt Tm Tb a50 x a50 x W W W Tb Tm a50 x Figure 5.2 5-1 ...
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