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05_InstSolManual_PDF_Part7

05_InstSolManual_PDF_Part7 - w w sin a w cos a T 1 x n A y...

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5.14. Set Up: The tension in C in each case is Apply to the knot where the three cords are joined. Use coordinates with upward and to the right. There is no motion and Solve: (a) The free-body diagram for the knot is given in Figure 5.14a. Tensions and are replaced by their x and y components. Figure 5.14 gives and gives Using gives and (b) The free-body diagram for the knot is given in Figure 5.14b. Tensions and are replaced by their x and y components. gives and gives Using gives and Then 5.15. Set Up: Apply to each block. Take perpendicular to the incline and parallel to the incline. Solve: The free-body diagrams for each block, A and B , are given in Figure 5.15. Figure 5.15 (a) For B , gives and (b) For block A , gives and (c) for each block gives (d) For and For and n A 5 n B 5 0. T 2 5 2 w T 1 5 w , a S 90°, n A 5 n B S w . T 1 5 T 2 S 0 a S 0, n A 5 n B 5 w cos a . g F y 5 ma y T 2 5 2 w sin a . T 1 2 T 2 2 w sin a5 0 g F x 5 ma x T 1 5 w sin a . T 1 2 w sin a5 0 g F x 5 ma x ( a
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Unformatted text preview: ) w w sin a w cos a T 1 x n A y a A ( b ) w w sin a w cos a T 2 T 1 x n B y B 1 x 1 y a 5 0. g F S 5 m a S T B 5 837 N. T A 5 683 N. 0.866 T A 2 0.500 T A 5 250 N T B 5 1.225 T A T B sin 45° 2 T A cos 60° 2 T C 5 0. g F y 5 T B 5 1.225 T A T B cos 45° 2 T A sin 60° 5 g F x 5 T B T A T B 5 1.225 T A 5 224 N. T A 5 183 N. 0.500 T A 1 0.866 T A 5 250 N T B 5 1.225 T A T A sin 30° 1 T B sin 45° 2 T C 5 0. g F y 5 T B 5 1.225 T A T B cos 45° 2 T A cos 30° 5 g F x 5 ( a ) T A sin30° T B sin45° T A T B sin45° T A cos30° x y T C 45° 45° 30° T B ( b ) T A T B sin45° T B cos45° T A sin60° T A cos60° x y T B T C 60° 60° T B T A a 5 0. 1 x 1 y g F S 5 m a S T C 5 250 N. Applications of Newton’s Laws 5-7...
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