05_InstSolManual_PDF_Part20

05_InstSolManual_PDF_Part20 - 7.39 m s 2 1 283 N 2 1 38.3...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
5.44. Set Up: (a) The free-body diagram for the person is given in Figure 5.44a. F is the traction force along the spinal column and is the person’s weight. (b) The free-body diagram for the collar where the cables are attached is given in Figure 5.44b. The tension in each cable has been resolved into its x and y components. Figure 5.44 Solve: (a) and (b) so 5.45. Set Up: The free-body diagram for the crate is given in Figure 5.45. Use coordinates with axes parallel and perpendicular to the ramp. Constant speed means The mass of the crate is The weight mg has been resolved into its x and y components. Figure 5.45 Solve: (a) gives with gives so (b) so and The acceleration would be directed down the ramp. Reflect: In part (a) the force up the incline is 283 N and the force down the incline is 283 N. When the rope breaks and the force down the incline remains 283 N. The acceleration down the incline is
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 7.39 m / s 2 . 1 283 N 2 / 1 38.3 kg 2 5 T S 0.754 g 5 7.39 m / s 2 , a x 5 2 g 1 m k cos f 1 sin f 2 5 2 0.754 g 2m k mg cos f 2 mg sin f 5 ma x 2 f k 2 mg sin f 5 ma x T 5 T 5 mg sin f 1 f k 5 1 375 N 2 sin 33° 1 1 0.250 21 375 N 2 cos 33° 5 283 N f k 5 0, T 2 mg sin f 2 a x 5 g F x 5 ma x f k 5 m k n 5 m k mg cos f . n 5 mg cos f . g F y 5 ma y mg y x n T f k mg sin f mg cos f f m 5 w / g 5 38.3 kg. a 5 0. T 5 F 2 sin 65° 5 0.75 w 2 sin 65° 5 0.41 w 5 1 0.41 21 9.80 m / s 2 21 78.5 kg 2 5 315 N 2 T sin 65° 2 F 5 F 5 f s 5 m s n 5 0.75 w 5 0.75 1 9.80 m / s 2 21 78.5 kg 2 5 577 N n 5 w F x y T cos65° T cos65° T sin65° T sin65° 65° 65° T T a 5 ( b ) ( a ) y x w n f s F a 5 w 5 mg 5-20 Chapter 5...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern