05_InstSolManual_PDF_Part25

05_InstSolManual_PDF_Part25 - f 5 mg g F y 5 ma y x 5 m 1 m...

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5.61. Set Up: The magnitude of the spring force is kx . The force diagrams are given in Figure 5.61. Figure 5.61 Solve: (a) and (b) and Reflect: Only the horizontal component of the spring force accelerates the sled, so a greater spring force is needed in part (b). 5.62. Set Up: The free-body diagrams are given in Figure 5.62. There is a kinetic friction force Figure 5.62 Solve: (a) and so (b) gives so and gives and x 5 m 1 m k g 1 a 2 k 1 cos f1m k sin f 2 5 1 9.50 kg 21 0.200 3 9.80 m / s 2 4 1 2.00 m / s 2 2 1 125 N / m 21 cos 30.0° 1 3 0.200 43 sin 30.0° 42 5 32.1 cm kx cos f2m k mg 1m k kx sin f5 ma kx cos f2 f k 5 ma g F x 5 ma x f k 5m k mg 2m k kx sin f n 5 mg 2 kx sin f n 1 kx sin
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Unformatted text preview: f 5 mg g F y 5 ma y x 5 m 1 m k g 1 a 2 k 5 1 9.50 kg 21 0.200 3 9.80 m / s 2 4 1 2.00 m / s 2 2 125 N / m 5 30.1 cm kx 2 m k mg 5 ma kx 2 f k 5 ma f k 5 m k mg . n 5 mg x kx y mg n n x kx y mg f k f k kx cos f kx sin f f a a f k 5 m k n . x 5 ma k cos 30.0° 5 0.152 m cos 30.0° 5 0.176 m 5 17.6 cm kx cos 30.0° 5 ma x 5 ma k 5 1 9.50 kg 21 2.00 m / s 2 2 125 N / m 5 0.152 m 5 15.2 cm kx 5 ma ( a ) x kx y w n ( b ) n x kx y w 30° kx cos30 ° a Applications of Newton’s Laws 5-25...
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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