Unformatted text preview: with the vertical. The tension T has been resolved into its x and y components. Figure 5.78 (b) gives and gives Combining these two equations gives so (c) As the rock becomes very heavy its acceleration approaches g ; and f S 45°. tan f S 1 f 5 12.5° tan f 5 a g 5 2.18 m / s 2 9.80 m / s 2 1 mg cos f 2 sin f 5 ma . T sin f 5 ma . g F x 5 ma x T 5 mg cos f . T cos f 2 mg 5 g F y 5 ma y x y T cos f T sin f T mg f f a 5 1 10.0 kg 21 9.80 m / s 2 2 45.0 kg 5 2.18 m / s 2 . 1 x 5.23 m / s 2 , a x 5 2 k x m 5 2 1 250 N / m 21 0.0230 m 2 1.10 kg 5 2 5.23 m / s 2 . 2 k x 5 ma x g F x 5 ma x k 5 ma x 5 1 1.10 kg 21 2.50 m / s 2 2 0.0110 m 5 250 N / m kx 5 ma g F x 5 ma x x y mg mg n kx ( a ) x y n ( b ) k x a k x x 532 Chapter 5...
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 Spring '07
 Shoberg
 Force, Mass, 2k, 2 mg, 5 2 m, 2.18 M

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