Unformatted text preview: Solve: (a) The tension in the cable must have a vertical component equal to the weight of the seat and passengers, no matter what the rotation rate is. It is not possible for the cable to be precisely horizontal, because then its tension would have no vertical component. (b) so and As the cable approaches horizontal, and T S ` . f S T 5 w sin f . T sin f 5 w T y 5 w y x T x w T y T f a rad 1 x f g F S 5 m a S T 5 2 p R v 5 2 p 1 5.50 m 2 5.58 m / s 5 6.19 s. v 5 " Rg tan u 5 "1 5.50 m 21 9.80 m / s 2 2 tan 30.0° 5 5.58 m / s. F sin 30.0° 5 m v 2 R . g F x 5 ma x F 5 mg cos 30.0° . F cos 30.0° 5 mg g F y 5 ma y F y F cos30° F sin30° 30° mg x a rad F S T 5 2 p R v . a rad 5 v 2 / R , R 5 3.00 m 1 1 5.00 m 2 sin 30.0° 5 5.50 m. m s 5 v 2 gR 5 1 25.0 m / s 2 2 1 9.80 m / s 2 21 220 m 2 5 0.290 m s mg 5 m v 2 R m s n 5 m v 2 R . g F x 5 ma x n 5 mg . g F y 5 ma y Circular Motion and Gravitation 63...
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 Spring '07
 Shoberg
 Acceleration, Circular Motion, Force, Mass, freebody diagram, Arad

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