06_InstSolManual_PDF_Part10

06_InstSolManual_PDF_Part10 - 3 10 2 11 N # m 2 / kg 2 2 1...

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Solve: The three masses and the forces on m are shown in Figure 6.23b. gives so and Reflect: Point P is closer to the smaller mass. 6.24. Set Up: The forces on A are shown in Figures 6.24a and 6.24b. Use the coordinates as shown. For (b) take the axis to be along the direction from A to D . Figure 6.24 Solve: (a) since The net force is in the direction from A toward the center of the line connecting B and C . (b) The distance between A and D is since and The net force is toward D . 6.25. Set Up: Let the masses be and and let be the initial force and let be the force after the parameters have changed. and where Solve: (a) gives (b) gives (c) gives gives (e) so The masses are the same so and d 2 5 " 2 d . 1 d 2 2 5 1 2 d 1 2 G m A 2 m B 2 d 2 2 5 1 2 G m A 1 m B 1 d 1 2 . F 2 5 F 1 / 2 F 2 5 G 1 2 m A 1 21 2 m B 1 2 1 d 1 / 2 2 2 5 16 F . d 2 5 d 1 / 2 m B 2 5 2 m B 1 , m A 2 5 2 m A 1 , F 2 5 G m A 1 m B 1 1 2 d 1 2 2 5 F / 4. d 2 5 2 d 1 F 2 5 G 1 3 m A 1 21 3 m B 1 2 d 1 2 5 9 F . m B 2 5 3 m B 1 m A 2 5 3 m A 1 , F 2 5 G 1 3 m A 1 2 m B 1 d 1 2 5 3 F . m A 2 5 3 m A 1 d 1 5 d . F 2 5 G m A 2 m B 2 d 2 2 , F 1 5 G m A 1 m B 1 d 1 2 F 2 F 1 5 F m B m A 1.15 3 10 2 7 N, F y 5 3.02 3 10 2 8 N 1 2 1 6.00 3 10 2 8 N 2 cos45° 5 1.15 3 10 2 7 N F y 5 F By 1 F Cy 1 F Dy 5 F D 1 2 F B cos 45° F Dx 5 0 F Cx 52 F Bx F x 5 F Bx 1 F Cx 1 F Dx 5 0, F B 5 F C 5 G m A m B r AB 2 5 1 6.673
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Unformatted text preview: 3 10 2 11 N # m 2 / kg 2 2 1 3.00 kg 2 2 1 0.100 m 2 2 5 6.00 3 10 2 8 N F D 5 G m A m D r AD 2 5 1 6.673 3 10 2 11 N # m 2 / kg 2 2 1 3.00 kg 2 2 1 0.141 m 2 2 5 3.02 3 10 2 8 N r AD 5 0.141 m. 1.04 3 10 2 7 N, F y 5 F By 1 F Cy 5 2 F B cos 30 5 1.04 3 10 2 7 N F Cx 5 2 F Bx F x 5 F Bx 1 F Cx 5 0, F B 5 F C 5 G m A m B r AB 2 5 1 6.673 3 10 2 11 N # m 2 / kg 2 2 1 3.00 kg 2 2 1 0.100 m 2 2 5 6.00 3 10 2 8 N. A F Bx F Cx F C F B x y F D B D C (b) 45 45 F Cy F By x y F Bx F By F Cy F Cx m A F B m B m C F C 30 30 (a) 1 y d 5 1.00 m 1 1 " 3 5 0.366 m 5 36.6 cm " 3 d 5 1.00 m 2 d 3 d 2 5 1 1.00 m 2 d 2 2 G mM d 2 5 G m 1 3 M 2 1 1.00 m 2 d 2 2 F 1 5 F 2 6-10 Chapter 6...
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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