06_InstSolManual_PDF_Part13

06_InstSolManual_PDF_Part13 - 5 2 p r T T 5 2 p r v v 2 5...

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6.35. Set Up: r and are related by applying to the satellite. Solve: gives and 6.36. Set Up: The mass of the sun is Solve: so 6.37. Set Up: The rotational period of the earth is The radius of the satellite’s path is where h is its height above the surface of the earth and and r are related by applying to the motion of the satellite. Solve: (a) (b)-(c) The free-body diagram for the satellite is given in Figure 6.37a. gives and so and Figure 6.37 (d) The sketch of the earth and orbit of the satellite is given in Figure 6.37b. Reflect: The orbital period is proportional to To achieve a period as large as 24 h, the satellite is at a large alti- tude above the earth’s surface. r 3 / 2 . r R E 5 5.6. h 5 r 2 R E 5 3.58 3 10 7 m 5 3.58 3 10 4 km r 5 1 Gm E T 2 4 p 2 2 1 / 3 5 S 1 6.673 3 10 2 11 N # m 2 / kg 2 21 5.97 3 10 24 kg 21 8.64 3 10 4 s 2 2 4 p 2 T 1 / 3 5 4.22 3 10 7 m r (b) Satellite E x y F g (a) a rad 4 p 2 r 2 T 2 5 Gm E r . v
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Unformatted text preview: 5 2 p r T T 5 2 p r v v 2 5 Gm E r . G m E m r 2 5 m v 2 r F g 5 ma rad 24 h 5 8.64 3 10 4 s m E 5 5.97 3 10 24 kg g F S 5 m a S v R E 5 6.38 3 10 6 m. r 5 h 1 R E , 1 day 5 8.64 3 10 4 s. m HD 5 1.2 m S m HD 5 4 p 2 r 3 T 2 G 5 4 p 2 1 10.5 3 10 9 m 2 3 1 5.443 3 10 5 s 2 2 1 6.673 3 10 2 11 N # m 2 / kg 2 2 5 2.3 3 10 30 kg; T 5 2 p r 3 / 2 " Gm HD m S 5 1.99 3 10 30 kg. T 5 6.3 days 5 5.443 3 10 5 s. r 5 10.5 3 10 9 m. v 5 Å Gm E r 5 Å 1 6.673 3 10 2 11 N # m 2 / kg 2 21 5.97 3 10 24 kg 2 7.16 3 10 6 m 5 7.46 3 10 3 m / s 5 7.46 km / s G m E m r 2 5 m v 2 r F g 5 ma rad 10 6 m 5 7.16 3 10 6 m r 5 h 1 R E 5 780 3 10 3 m 1 6.38 3 g F S 5 m a S v Circular Motion and Gravitation 6-13...
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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