06_InstSolManual_PDF_Part15

06_InstSolManual_PDF_Part15 - T 2 4 p 2 2 1 3 Gm E r 5 4 p...

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6.41. Set Up: The mass of the earth is Solve: (a) The radius of the event horizon for a black hole of mass is (b) Your mass is Reflect: The calculation in (b) assumes that you can be treated as a point mass, with all of your mass at the event horizon. 6.42. Set Up: Apply to the motion of the baseball. Solve: gives which is easy to achieve. 6.43. Set Up: The satellite makes 15.65 revolutions in Solve: (a) The free-body diagram for the satellite is given in Figure 6.43. Figure 6.43 (b) so and and so 6.44. Set Up: The distance a point on the rim travels in 1 revolution is Solve: so In one minute a point on the rim travels a distance The number of revolutions in one minute is The station must turn at 2.55 rpm. 2202 m 2 p r 5 2.55. 1 36.7 m / s 21 60 s 2 5 2202 m. v 5 " ra rad 5 "1 137.5 m 21 9.80 m / s 2 2 5 36.7 m / s a rad 5 v 2 R 2 p r . r 5 137.5 m. h 5 r 2 R E 5 3.7 3 10 5 m 5 370 km r 5 S 1 6.673 3 10 2 11 N # m 2 / kg 2 21 5.97 3 10 24 kg 21 5.52 3 10 3 s 2 2 4 p 2 T 1 / 3 5 6.75 3 10 6 m r 5 1 Gm E
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Unformatted text preview: T 2 4 p 2 2 1 / 3 , Gm E r 5 4 p 2 r 2 T 2 . v 2 5 4 p 2 r 2 T 2 . T 5 2 p r v Gm E r 5 v 2 G mm E r 2 5 m v 2 r F g 5 m v 2 r T 5 8.64 3 10 4 s 15.65 5 5.52 3 10 3 s R E r v F g 8.64 3 10 4 s 1 day 5 R E 5 6.38 3 10 6 m. m E 5 5.97 3 10 24 kg, 4.7 m / s 5 11 mph, v 5 Å Gm D r D 5 Å 1 6.673 3 10 2 11 N # m 2 / kg 2 21 2.0 3 10 15 kg 2 6 3 10 3 m 5 4.7 m / s G m D m r D 2 5 m v 2 r D . F g 5 ma rad r D 5 6 3 10 3 m. g F S 5 m a S F g 5 G mm E R S 2 5 1 6.673 3 10 2 11 N # m 2 / kg 2 21 76.5 kg 21 5.97 3 10 24 kg 2 1 8.85 3 10 2 3 m 2 2 5 3.89 3 10 20 N m 5 w / g 5 76.5 kg. R S 5 2 Gm E c 2 5 2 1 6.673 3 10 2 11 N # m 2 / kg 2 21 5.97 3 10 24 kg 2 1 3.00 3 10 8 m / s 2 2 5 8.85 3 10 2 3 m m E m E 5 5.97 3 10 24 kg. Circular Motion and Gravitation 6-15...
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