06_InstSolManual_PDF_Part19

06_InstSolManual_PDF_Part19 - B1 2.5 3 10 3 m 2 3 5 1.374 3...

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Reflect: and so which agrees with the value calculated in part (a). 6.54. Set Up: Equating the weight to gives where is the length of her leg. Solve: At the surface of Europa, 6.55. Set Up: The volume of a sphere is The mass of Sedna is where The mass of the astronaut is Solve: Then Reflect: g is much less on Sedna so w is much less there. 6.56. Set Up: The comet has radius volume and density Solve: (a) The comet has mass The gravitational force is (b) At the surface of the earth the earth’s gravity force is The force exerted by the comet is much less than this. 6.57. Set Up: The block moves in a horizontal circle of radius Each string makes an angle with the vertical. so The block has acceleration directed to the left in the figure in the problem. a rad 5 v 2 / r , u5 36.9°. cos u5 1.00 m 1.25 m , u r 5 "1 1.25 m 2 2 2 1 1.00 m 2 2 5 0.75 m. w 5 mg 5 1 385 kg 21 9.80 m / s 2 2 5 3.77 3 10 3 N. F g 5 G mm C r 2 5 1 6.673 3 10 2 11 N # m 2 / kg 2 21 385 kg 21 1.374 3 10 14 kg 2 1 237 3 10 3 m 2 2 5 6.28 3 10 2 5 N m C 5r C V C 5r C 4 3 p R 3 5 1 2.1 3 10 3 kg / m 3 2A 4 3 p
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Unformatted text preview: B1 2.5 3 10 3 m 2 3 5 1.374 3 10 14 kg. r 5 2.1 3 10 3 kg / m 3 . V 5 4 3 p R 3 R 5 2.5 3 10 3 m, w 5 mg 5 1 68.9 kg 21 0.499 m / s 2 2 5 34.4 N. g 5 G m S R S 2 5 1 6.673 3 10 2 11 N # m 2 / kg 2 21 5.40 3 10 21 kg 2 1 8.5 3 10 5 m 2 2 5 0.499 m / s 2 m S 5 r S V S 5 r S 4 3 p R 3 5 1 2.1 3 10 3 kg / m 3 2A 4 3 p B1 8.5 3 10 5 m 2 3 5 5.40 3 10 21 kg m 5 w g 5 675 N 9.80 m / s 2 5 68.9 kg r S 5 2.1 3 10 3 kg / m 3 . m S 5 r S V S , m S R S 5 8.5 3 10 5 m. V 5 4 3 p R 3 . v max 5 "1 1.30 m / s 2 21 1.0 m 2 5 1.1 m / s g 5 G m Europa R Europa 2 5 1 6.673 3 10 2 11 N # m 2 / kg 2 21 4.78 3 10 22 kg 2 1 1.565 3 10 6 m 2 2 5 1.30 m / s 2 R 5 1.0 m v max 5 " gR , ma rad R Europa 5 1.565 3 10 6 m. g M 5 7.6 1 5.0 2 2 g E 5 0.30 g E , m M 5 7.6 m E , R M 5 5.0 R E Circular Motion and Gravitation 6-19...
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