06_InstSolManual_PDF_Part22

06_InstSolManual_PDF - F MD F M 5 1 Gmm MD r MD 2 21 d 2 Gmm M 2 5 1 d r MD 2 2 1 m MD m M 2 5 1 7.8 3 10 10 m 0.50 m 2 2 1 75 kg 6.42 3 10 23 kg 2

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At the equator Sneezy is traveling in a circular path and has acceleration gives and Reflect: At the equator the object has an inward acceleration and the outward tension is less than the true weight, since there is a net inward force. 6.62. Set Up: Mars has mass Mars has orbit radius Earth has orbit radius Assume that the orbits of earth and Mars lie in the same plane. Solve: (a) Mars is closest to the earth when they are in the positions sketched in Figure 6.62. This closest distance is Figure 6.62 (b) where and m is the mass of the baby. (c) The two forces are comparable, but at this distance from the baby the MD exerts a larger force. The gravitational influence of Mars is no more than the gravitational influence of people in the room with the baby.
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Unformatted text preview: F MD F M 5 1 Gmm MD r MD 2 21 d 2 Gmm M 2 5 1 d r MD 2 2 1 m MD m M 2 5 1 7.8 3 10 10 m 0.50 m 2 2 1 75 kg 6.42 3 10 23 kg 2 5 2.8 F M 5 Gmm M d 2 . r MD 5 0.50 m m MD 5 75 kg, F MD 5 Gmm MD r MD 2 , Sun Earth Mars r E r M d 5 r M 2 r E 5 7.8 3 10 10 m. r E 5 1.50 3 10 11 m. r M 5 2.28 3 10 11 m. m M 5 6.42 3 10 23 kg. T 5 w 2 ma rad 5 m 1 g 2 a rad 2 5 1 48.47 kg 21 9.80 m / s 2 2 0.0337 m / s 2 2 5 473.4 N w 2 T 5 ma rad g F y 5 ma y a rad 5 4 p 2 R T 2 5 4 p 2 1 6.38 3 10 6 m 2 1 8.64 3 10 4 s 2 2 5 0.0337 m / s 2 6-22 Chapter 6...
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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