8.44.Set Up:Let be to the right and be upward.Solve: (a)The horizontal component is to the left and the vertical component is upward.(b)The horizontal component is 8800 N, to the left, and the vertical component is 2690 N, upward.8.45.Set Up:Represent each atom as a point. Use coordinates with the origin at the carbon atom and with theoxygen atom on the axis.Solve:and so The center of mass is along the line connecting the two atoms, 0.063 nm from the carbon atom and 0.048 nm fromthe oxygen atom.Reflect:The center of mass is closer to the more massive oxygen atom.8.46.Set Up:Since the beam is uniform, all its mass can be considered to be at its center. The mass of the beam isLet and For each choice of origin let the axis lie along the beam.Solve: (a)and The center of mass is 1.29 m from the left-hand end of the beam.(b)Now and The center of mass is 1.71 m from the right-hand end of the beam and therefore 1.29 m from the left-hand end.
This is the end of the preview.
access the rest of the document.