09_InstSolManual_PDF_Part1

09_InstSolManual_PDF_Part1 - ROTATIONAL MOTION 9 8. A, C 9....

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Unformatted text preview: ROTATIONAL MOTION 9 8. A, C 9. C 10. C 11. C 12. A 13. B 14. A 15. A 16. A Answers to Multiple-Choice Problems 1. B 2. D 3. C 4. C 5. A 6. D 7. B Solutions to Problems 9.1. Set Up: u 5 s gives u in radians. 2p rad 5 360°. r 0.750 m 360° Solve: u 5 5 17.2° 5 0.300 rad; 1 0.300 rad 2 2.50 m 2p rad 9.2. Set Up: p rad 5 180°. s 5 ru, with u in radians. 1.50 m s 5 5 0.600 rad 5 34.4° r 2.50 m 14.0 cm s (b) r 5 5 5 6.27 cm u 1 128° 2 1 p rad / 180° 2 Solve: (a) u 5 (c) s 5 ru 5 1 1.50 m 2 1 0.700 rad 2 5 1.05 m 1 2 9.3. Set Up: For one revolution, Du 5 2p rad. Assume constant angular velocity, so Du . Dt The second hand makes 1 revolution in 1 minute 5 60.0 s. The minute hand makes 1 revolution in 1 h 5 3600 s, and the hour hand makes 1 revolution in 12 h 5 43,200 s. 2p rad 5 0.105 rad / s; Solve: (a) second hand v 5 60 s 2p rad 5 1.75 3 1023 rad / s; minute hand v 5 3600 s 2p rad 5 1.45 3 1024 rad / s hour hand v 5 43,200 s (b) The period is the time for 1 revolution. Second hand, 1min; minute hand, 1 h; hour hand, 12 h. Reflect: When the angular velocity is constant, v 5 v av . v5 9.4. Set Up: 33 1 rpm 5 0.5556 rev / s is the angular speed. 3 Solve: (a) 1 0.5556 rev / s 2 2p rad 5 3.49 rad / s 1 rev 1 rev u (b) For 1 rev, t 5 5 5 1.80 s v 0.5556 rev / s 1 2 9.5. Set Up: 1 rev 5 2p rad Solve: (a) The period is the time for 1 rev, so period 5 2.25 s. 9-1 ...
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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