10_InstSolManual_PDF_Part1

10_InstSolManual_PDF_Part1 - 21 0.20 m 2 sin 90° 5 2 10.0...

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10-1 D YNAMICS OF R OTATIONAL M OTION 10 Answers to Multiple-Choice Problems 1. C 2. C 3. E 4. B 5. B 6. D 7. A 8. D 9. C 10. B 11. C 12. D 13. C 14. E 15. D Solutions to Problems 10.1. Set Up: Let counterclockwise torques be positive. with Solve: (a) counterclockwise. (b) counterclockwise. (c) counterclockwise. (d) clockwise. (e) since the force acts on the axis and (f) since the line of action of the force passes through the location of the axis and Reflect: The torque of a force depends on the direction of the force and where it is applied to the object. 10.2. Set Up: Let counterclockwise torques be positive. with Solve: The net torque is clockwise. 10.3. Set Up: Let counterclockwise torques be positive. Solve: The net torque is clockwise. 10.4. Set Up: Let counterclockwise torques be positive. Solve: (a) counterclockwise. clockwise. clockwise. clockwise. t C 1t D 52 6.3 N # m, g t5t A 1t B 1 t D 52 1 50 N
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Unformatted text preview: 21 0.20 m 2 sin 90° 5 2 10.0 N # m, sin 30° 5 2 5.0 N # m, t C 5 2 1 50 N 21 0.20 m 2 t B 5 0. t A 5 1 1 50 N 21 0.20 m 2 sin 60° 5 1 8.7 N # m, t 5 Fl 0.73 N # m, g t 5 t 1 1 t 2 5 2 0.73 N # m. t 2 5 1 F 2 R 5 2 1 5.30 N 21 0.330 m 2 5 1 1.75 N # m. t 1 5 2 F 1 R 5 2 1 7.50 N 21 0.330 m 2 5 2 2.48 N # m. t 5 Fl 28.0 N # m, g t 5 t 1 1 t 2 5 2 28.0 N # m. t 2 5 1 F 2 l 2 5 1 12.0 N 21 2.00 m 2 sin 30.0° 5 1 12.0 N # m. t 1 5 2 F 1 l 1 5 2 1 8.00 N 21 5.00 m 2 5 2 40.0 N # m. l 5 r sin f . t 5 Fl l 5 0. t 5 l 5 t 5 t 5 2 1 10.0 N 21 2.00 m 2 sin 60.0° 5 2 17.3 N # m, t 5 1 1 10.0 N 21 4.00 m 2 sin 30.0° 5 20.0 N # m, t 5 1 1 10.0 N 21 4.00 m 2 sin 60.0° 5 34.6 N # m, t 5 1 1 10.0 N 21 4.00 m 2 sin 90.0° 5 40.0 N # m, l 5 r sin f . t 5 Fl...
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