10_InstSolManual_PDF_Part12

10_InstSolManual_PDF_Part12 - 10.40 Set Up Apply with...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
10.38. Set Up: The free-body diagram for the board is given in Figure 10.38. Since the board is uniform its center of gravity is 1.50 m from each end. Apply with upward. Apply with the axis at the end where the first person applies a force and with counterclockwise torques positive. Figure 10.38 Solve: gives and gives and The second person lifts with a force of 100 N at a point 2.40 m from the end where the first person lifts. 10.39. Set Up: The free-body diagram is given in Figure 10.39. is the force on each foot and is the force on each hand. Use coordinates as shown. Take the pivot at his feet and let counterclockwise torques to be positive. Figure 10.39 Solve: gives gives and Reflect: His center of mass is closer to his hands than to his feet, so his hands exert a greater force.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 10.40. Set Up: Apply with upward, and apply with the axis at the left-hand end and counterclockwise torques positive. Solve: (a) The free-body diagram for the board is given in Figure 10.40. Figure 10.40 Axis w m x 2.00m F 2 F 1 g t 5 0, 1 y g F y 5 0, F f 5 1 2 w 2 F h 5 402 N 2 272 N 5 130 N 2 F f 1 2 F h 2 w 5 g F y 5 F h 5 w 1.15 m 2 1 1.70 m 2 5 0.338 w 5 272 N 1 1 2 F h 21 1.70 m 2 2 w 1 1.15 m 2 5 g t 5 2 F f 2 F h 1.70m 1.15m Pivot 0.55m 0.30m y w x 1 F h F f x 5 1 w F 2 2 1 1.50 m 2 5 1 160 N 100 N 2 1 1.50 m 2 5 2.40 m. w 1 1.50 m 2 5 F 2 x 2 g t 5 F 2 5 w 2 F 1 5 160 N 2 60 N 5 100 N. F 1 1 F 2 2 w 5 g F y 5 Axis 1.50m cg F 2 F 1 w x g t 5 1 y g F y 5 0, 10-12 Chapter 10...
View Full Document

This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

Ask a homework question - tutors are online