College Physics, Young,Geller CH10-CH15

College Physics, Young,Geller CH10-CH15 - center of gravity...

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(b) gives and (c) gives The center of gravity of the motor is 1.20 m from the end where the 400.0 N force is applied. 10.41. Set Up: The free-body diagram for the wheelbarrow is given in Figure 10.41. The wheel is at the right-hand end and the ground applies a force there. Apply with the axis at the right-hand end and counterclockwise torques positive. Figure 10.41 Solve: (a) (b) The additional force comes from the ground. 10.42. Set Up: The free-body diagram for Clea is given in Figure 10.42. Apply with upward and with the axis at her hind feet and counterclockwise torque positive. Figure 10.42 Solve: gives and gives Clea weighs 246 N and her center of gravity is 0.61 m from her hind feet, so is 0.34 m from her front feet. 10.43. Set Up: The free-body diagram for the beam is given in Figure 11.43. and are the vertical and horizontal components of the force exerted on the beam at the wall (by the hinge). Since the beam is uniform, its
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Unformatted text preview: center of gravity is 2.00 m from each end. The angle has and The tension T has been replaced by its x and y components. sin u 5 0.600. cos u 5 0.800 u H h H v x 5 1 n f w 2 1 0.95 m 2 5 1 157 N 246 N 2 1 0.95 m 2 5 0.61 m. n f 1 0.95 m 2 2 wx 5 0. g t 5 w 5 157 N 1 89 N 5 246 N. n h 1 n f 2 w 5 g F y 5 0.95m x axis n f n h w 1 g t 5 1 y g F y 5 w load 5 900 N # m 2 56 N # m 0.70 m 5 1.21 3 10 3 N 2 1 450 N 21 2.00 m 2 1 w load 1 0.70 m 2 1 1 80 N 21 0.70 m 2 5 0. 2.0m 0.70m axis w load 450N 80N F ground 1 g t 5 F ground x 5 1 F 2 w m 2 1 2.00 m 2 5 1 600.0 N 1000 N 2 1 2.00 m 2 5 1.20 m F 2 1 2.00 m 2 2 w m x 5 0. g t 5 w m 5 1000 N. F 1 1 F 2 2 w m 5 g F y 5 Dynamics of Rotational Motion 10-13...
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