Unformatted text preview: that opposes the torque due to w . 10.48. Set Up: The center of gravity of the beam is 2.0 m from the hinge. Use coordinates with upward and to the right. Take the pivot at the hinge and let counterclockwise torque be positive. Solve: (a) The freebody diagram for the beam is shown in Figure 10.48. The tension T in the wire has been replaced by its x and y components. Figure 10.48 y w b w T cos60 ° T sin60 ° x H v H h Pivot Hinge 2.0m 0.5m 1.5m 1 60 ° 1 x 1 y H v H h H v T cos f , H v 5 1 1.00 kN 21 sin 53.1° 2 2 530 N 5 270 N T sin f 2 H v 2 w 5 g F y 5 H h 5 1 1.00 kN 21 cos 53.1° 2 5 600 N H h 2 T cos f 5 g F x 5 w 5 1 T sin f 21 3.0 m 2 4.5 m 5 1 1.00 kN 21 sin 53.1° 21 3.0 m 2 4.5 m 5 530 N 1 T sin f 21 3.0 m 2 2 w 1 4.5 m 2 5 g t 5 T cos f T sin f Hinge Pivot y x 3.0m 4.5m H h H v T w f 1 T 5 1.00 kN. H h H v H h . H v 1 x 1 y f 5 53.1°. sin f 5 4.0 m 5.0 m f 1016 Chapter 10...
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 Spring '07
 Shoberg
 Center Of Mass, Force, Gravity, Political spectrum, Hinge, hV

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