10_InstSolManual_PDF_Part17 - Dynamics of Rotational Motion...

Info icon This preview shows page 1. Sign up to view the full content.

(b) gives (c) gives and gives and 10.49. Set Up: The free-body diagram for the leg is given in Figure 10.49. Take the pivot at the hip joint and let counterclockwise torque be positive. There are also forces on the leg exerted by the hip joint but these forces produce no torque and aren’t shown. Figure 10.49 Solve: (a) gives and for (b) For The tension is much greater when he just starts to raise his leg off the ground. (c) as The person could not raise his leg. If the leg is horizontal so is zero, the moment arm for T is zero and T produces no torque to rotate the leg against the torque due to its weight. 10.50. Set Up: Take the pivot at the left-hand end of the branch and let counterclockwise torque be positive. The trunk exerts a force on the branch at its left-hand end. The wood fiber exerts a force at a point from the left-hand end of the branch.
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Solve: (a) The free-body diagram is given in Figure 10.50. Figure 10.50 (b) gives T 5 1 1.75 m 21 60 kg 21 9.80 m / s 2 2 1 0.162 m 2 sin 45° 5 9000 N T sin 45° 1 0.162 m 2 2 w 1 1.75 m 2 5 g t 5 1.75m 0.162m T cos45° T sin45° T F v F h w Pivot 1 45° 1 4 1 0.65 m 2 5 0.162 m T S F S u u S 0. T S ` T 5 7400 N. u 5 5°, T 5 4.4 1 15 kg 21 9.80 m / s 2 2 tan 60° 5 370 N u 5 60°, T 5 4.4 w cos u sin u 5 4.4 w tan u T 1 10 cm 21 sin u 2 2 w 1 44 cm 21 cos u 2 5 g t 5 u w 10cm T 34cm Pivot 1 H v 5 w b 1 w 2 T cos 60.0° 5 2560 N H v 1 T cos 60.0° 2 w b 2 w 5 g F y 5 H h 5 T sin 60.0° 5 5960 N H h 2 T sin 60.0° 5 g F x 5 T 5 1 2500 N 21 2.00 m 2 1 1 3500 N 21 2.50 m 2 2.00 m 5 6880 N 1 T cos 60.0° 21 4.0 m 2 2 w b 1 2.0 m 2 2 w 1 2.5 m 2 5 g t 5 Dynamics of Rotational Motion 10-17...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern