Unformatted text preview: Figure 10.52 (b) gives (c) gives gives so Since we calculate to be positive, we correctly assumed that it was downward when we drew the freebody diagram. (d) The factor divides out of the equation in part (b), so the force T stays the same as she raises her arm. g t 5 cos u E v E v 5 T 2 w arm 2 w 5 569 N 2 1 2.16 kg 21 9.80 m / s 2 2 2 1 7.50 kg 21 9.80 m / s 2 2 5 474 N T 2 E v 2 w arm 2 w 5 0, g F y 5 E h 5 0. g F x 5 T 5 16.0 w arm 1 38.0 w 5.5 5 16.0 1 2.16 kg 21 9.80 m / s 2 2 1 38.0 1 7.50 kg 21 9.80 m / s 2 2 5.5 5 569 N T 1 5.5 cm 21 cos u 2 2 w arm 1 16.0 cm 21 cos u 2 2 w 1 38.0 cm 21 cos u 2 5 g t 5 w w arm y x T 10.5cm 22.0cm pivot E v E h u 5.5cm E h . E v E S T S m 5 7.50 kg. w 5 mg , m arm 5 1 2 1 0.0600 21 72 kg 2 5 2.16 kg. 1 x 1 y f L h 5 U h 5 140 N. g F x 5 U h 5 1 0.50 m 1.00 m 2 1 280 N 2 5 140 N. 2 w 1 0.50 m 2 1 U h 1 1.00 m 2 5 g t 5 0.50m 1.00m 0.50m U h L h L v U v w cg 0.50m 1 U v 5 L v 5 w / 2 5 140 N. L h L v , U h U v , 1018 Chapter 10...
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 Spring '07
 Shoberg
 Force

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