10_InstSolManual_PDF_Part24

10_InstSolManual_PDF_Part24 - v f 5 1 I i I f 2 v i 5 1...

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(b) Conservation of angular momentum applied to the collision gives so (c) The final position of Tarzan and Jane, when they have swung to their maximum height, is shown in Figure 10.65b. If Tarzan and Jane rise to a height h , then the center of the vine rises to a height Conservation of energy gives where and from part (b). Figure 10.65 Reflect: Mechanical energy is lost in the inelastic collision. 10.66. Set Up: Let the length of the beam be L . The free-body diagram for the beam is given in Figure 10.66. Figure 10.66 x y T w 40 ° n Axis 160 ° 20 ° 40 ° f s L 2 L 2 h 5 I v 2 2 1 m Jane 1 m Tarzan 1 0.5 m vine 2 g 5 1 9.09 3 10 3 kg # m 2 21 0.631 rad / s 2 2 2 1 60.0 kg 1 72.0 kg 1 15.0 kg 21 9.80 m / s 2 2 5 1.26 m ( b ) h 2 4.00m 4.00m Center of vine h Jane 1 Tarzan u v5 0.631 rad / s, I 5 9.09 3 10 3 kg # m 2 1 2 I v 2 5 1 m Jane 1 m Tarzan 2 gh 1 m vine gh / 2, h / 2.
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Unformatted text preview: v f 5 1 I i I f 2 v i 5 1 4.48 3 10 3 kg # m 2 9.09 3 10 3 kg # m 2 2 1 1.28 rad / s 2 5 0.631 rad / s I f 5 I i 1 m Tarzan l 2 5 4.48 3 10 3 kg # m 2 1 1 72.0 kg 21 8.00 m 2 2 5 9.09 3 10 3 kg # m 2 I i 5 C 1 3 1 30.0 kg 2 1 60.0 kg D1 8.00 m 2 2 5 4.48 3 10 3 kg # m 2 v i 5 1.28 rad / s. I i v i 5 I f v f . L i 5 L f , v 5 2 31 60.0 kg 21 5.00 m 2 1 1 30.0 kg 21 2.50 m 241 9.80 m / s 2 2 C 1 3 1 30.0 kg 2 1 60.0 kg D1 8.00 m 2 2 5 1.28 rad / s v 5 2 3 m Jane 1 5.00 m 2 1 m vine 1 2.50 m 24 g A 1 3 m vine 1 m Jane B l 2 m Jane g 1 5.00 m 2 1 m vine g 1 6.50 m 2 5 m vine g 1 4.00 m 2 1 1 2 I tot v 2 10-24 Chapter 10...
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