11_InstSolManual_PDF_Part9

# 11_InstSolManual_PDF_Part9 - Elasticity and Periodic Motion...

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The acceleration is maximum when and this occurs at the times given in (d). (f) so Reflect: The speed is maximum at when The magnitude of the acceleration is maximum at where 11.42. Set Up: Solve: (a) (b) (c) 11.43. Set Up: Solve: (a) (b) Solving for gives Reflect: When the mass increases, the frequency of oscillation increases. 11.44. Set Up: Solve: so 11.45. Set Up: The motion specified is one-half of a cycle so the time is Solve: so Reflect: The period of a simple pendulum does not depend on its amplitude, as long as the amplitude is small, and does not depend on the mass of the bob. The period depends only on the length of the pendulum and the value of g . 11.46. Set Up: The motion specified is one-fourth of a cycle, so Solve: so The answer doesn’t depend on the mass of the bob or the amplitude of the swing. L 5 g 1 T 2 p 2 2 5 1 9.80 m / s 2 2 1 4.52 s 2 p 2 2 5 5.07 m T 5 2 p Å L g T 5 4 t 5 4 1 1.13 s 2 5 4.52 s t 5 T / 4. t 5 1.88 s T 5 2 p Å 3.50 m 9.80 m / s 2 5
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Unformatted text preview: / s 2 5 3.75 s, t 5 T / 2. T 5 2 p Å L g . L 5 g 1 T 2 p 2 2 5 1 9.80 m / s 2 2 1 3.40 s 2 p 2 2 5 2.87 m T 5 85.0 s 25.0 5 3.40 s T 5 2 p Å L g m V 5 9.99 femtograms m v 5 m s 1S f s f s 1 v T 2 2 1 2 5 1 2.10 3 10 2 16 g 2 1S 2.00 3 10 15 Hz 2.87 3 10 14 Hz T 2 2 1 2 5 9.99 3 10 2 15 g m v 1 f s 1 v f s 2 2 5 1 1 1 m v / m s . f s 1 v f s 5 1 1 2 p Å k m s 1 m v 21 2 p Å m s k 2 5 Å m s m s 1 m v 5 1 " 1 1 m v / m s f s 1 v 5 1 2 p Å k m s 1 m v f s 5 1 2 p Å k m s , f 5 1 2 p Å k m m 5 k v 2 5 120 N / m 1 37.7 rad / s 2 2 5 0.0844 kg v 5 2 p f 5 2 p 1 6.00 Hz 2 5 37.7 rad / s T 5 1 f 5 1 6.00 Hz 5 0.167 s T 5 1 f . f 5 v 2 p 5 1 2 p Å k m . v x 5 0. x 5 6 A , a x 5 0. x 5 0, m 5 k 1 T 2 p 2 2 5 1 75 N / m 2 1 1.60 s 2 p 2 2 5 4.9 kg T 5 2 p Å m k x 5 6 A Elasticity and Periodic Motion 11-9...
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• Spring '07
• Shoberg
• Acceleration, 3.50 m, 1 37.7 rad, 2 5 4.9 kg, 2 5 37.7 rad, 5 1 k

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