11_InstSolManual_PDF_Part12

11_InstSolManual_PDF_Part12 - than those of earth. m 5 gR 2...

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11.56. Set Up: M is the mass of the empty car and the mass of the loaded car is Solve: The period of the empty car is The period of the loaded car is 11.57. Set Up: Relative to the accelerating rocket, the downward acceleration of an object that is dropped inside the rocket is the rock is accelerated downward by gravity and the rocket accelerates upward toward the rock. Solve: Use the period when the rocket is at rest to calculate the length of the pendulum. When the rocket is accelerating, and Reflect: If the rocket had a downward acceleration, as an elevator might, then the period decreases. If the rocket is in free-fall, with downward acceleration g , then the pendulum bob doesn’t swing at all and the period is infinite. 11.58. Set Up: Solve: so so 11.59. Set Up: the motion from one position of to the next is half a period. The period depends only on g and where m and R are the mass and radius of Newtonia. The circumference c is related to R by Solve: gives Reflect: The value of G on Newtonia is within 10% of the value on earth. The mass and radius are somewhat larger
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Unformatted text preview: than those of earth. m 5 gR 2 G 5 1 9.06 m / s 2 21 8.18 3 10 6 m 2 2 6.673 3 10 2 11 N # m 2 / kg 2 5 9.08 3 10 24 kg R 5 c 2 p 5 5.14 3 10 7 m 2 p 5 8.18 3 10 6 m. g 5 1 2 p T 2 2 L 5 1 2 p 2.84 s 2 2 1 1.85 m 2 5 9.06 m / s 2 . T 5 2 p Å L g T 5 2 1 1.42 s 2 5 2.84 s. G 5 6.673 3 10 2 11 N # m 2 / kg 2 . c 5 2 p R . g 5 G m R 2 , v 5 K 5 3 4 E . K 1 U 5 E U 5 1 4 A 1 2 kA 2 B 5 1 4 E . x 5 A 2 U 5 1 2 kx 2 E 5 1 2 kA 2 5 K 1 U . a 5 39.2 m / s 2 2 9.80 m / s 2 5 29.4 m / s 2 . g 1 a 5 L 1 2 p T 2 2 5 1 1.55 m 2 1 2 p 1.25 s 2 2 5 39.2 m / s 2 T 5 2 p Å L g 1 a . L 5 g 1 T 2 p 2 2 5 1 9.80 m / s 2 2 1 2.50 s 2 p 2 2 5 1.55 m T 5 2.50 s a 1 9.80 m / s 2 ; T 5 2 p Å L g . T E 5 2 p Å 1.56 3 10 3 kg 6.125 3 10 4 N / m 5 1.00 s M 5 1 T L 2 p 2 2 k 2 250 kg 5 1 1.08 s 2 p 2 2 1 6.125 3 10 4 N / m 2 2 250 kg 5 1.56 3 10 3 kg. k 5 1 250 kg 21 9.80 m / s 2 2 4.00 3 10 2 2 m 5 6.125 3 10 4 N / m T L 5 2 p Å M 1 250 kg k . T E 5 2 p Å M k . M 1 250 kg. T 5 2 p Å m k . 11-12 Chapter 11...
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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