11_InstSolManual_PDF_Part12

# 11_InstSolManual_PDF_Part12 - 11-12 Chapter 11 11.56 Set Up...

• Notes
• 1

This preview shows page 1. Sign up to view the full content.

11.56. Set Up: M is the mass of the empty car and the mass of the loaded car is Solve: The period of the empty car is The period of the loaded car is 11.57. Set Up: Relative to the accelerating rocket, the downward acceleration of an object that is dropped inside the rocket is the rock is accelerated downward by gravity and the rocket accelerates upward toward the rock. Solve: Use the period when the rocket is at rest to calculate the length of the pendulum. When the rocket is accelerating, and Reflect: If the rocket had a downward acceleration, as an elevator might, then the period decreases. If the rocket is in free-fall, with downward acceleration g , then the pendulum bob doesn’t swing at all and the period is infinite. 11.58. Set Up: Solve: so so 11.59. Set Up: the motion from one position of to the next is half a period. The period depends only on g and where m and R are the mass and radius of Newtonia. The circumference c is related to R by Solve: gives Reflect: The value of G on Newtonia is within 10% of the value on earth. The mass and radius are somewhat larger
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: than those of earth. m 5 gR 2 G 5 1 9.06 m / s 2 21 8.18 3 10 6 m 2 2 6.673 3 10 2 11 N # m 2 / kg 2 5 9.08 3 10 24 kg R 5 c 2 p 5 5.14 3 10 7 m 2 p 5 8.18 3 10 6 m. g 5 1 2 p T 2 2 L 5 1 2 p 2.84 s 2 2 1 1.85 m 2 5 9.06 m / s 2 . T 5 2 p Å L g T 5 2 1 1.42 s 2 5 2.84 s. G 5 6.673 3 10 2 11 N # m 2 / kg 2 . c 5 2 p R . g 5 G m R 2 , v 5 K 5 3 4 E . K 1 U 5 E U 5 1 4 A 1 2 kA 2 B 5 1 4 E . x 5 A 2 U 5 1 2 kx 2 E 5 1 2 kA 2 5 K 1 U . a 5 39.2 m / s 2 2 9.80 m / s 2 5 29.4 m / s 2 . g 1 a 5 L 1 2 p T 2 2 5 1 1.55 m 2 1 2 p 1.25 s 2 2 5 39.2 m / s 2 T 5 2 p Å L g 1 a . L 5 g 1 T 2 p 2 2 5 1 9.80 m / s 2 2 1 2.50 s 2 p 2 2 5 1.55 m T 5 2.50 s a 1 9.80 m / s 2 ; T 5 2 p Å L g . T E 5 2 p Å 1.56 3 10 3 kg 6.125 3 10 4 N / m 5 1.00 s M 5 1 T L 2 p 2 2 k 2 250 kg 5 1 1.08 s 2 p 2 2 1 6.125 3 10 4 N / m 2 2 250 kg 5 1.56 3 10 3 kg. k 5 1 250 kg 21 9.80 m / s 2 2 4.00 3 10 2 2 m 5 6.125 3 10 4 N / m T L 5 2 p Å M 1 250 kg k . T E 5 2 p Å M k . M 1 250 kg. T 5 2 p Å m k . 11-12 Chapter 11...
View Full Document

• Spring '07
• Shoberg

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern