12_InstSolManual_PDF_Part6 - where L is the length of the...

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Solve: (a) and (b) The two waves and their sum are shown in Figure 12.20. Figure 12.20 12.21. Set Up: is the time for one cycle. For and this is the distance along the time axis occupied by one cycle of this wave. For and for The net displacement is the algebraic sum of the displacements due to each wave. Solve: The three waves and their sum are shown in Figure 12.21. Figure 12.21 Reflect: The net sound wave is periodic, with period 2.70 ms, but it is not sinusoidal. 12.22. Set Up: For the first harmonic,
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Unformatted text preview: where L is the length of the vibrating portion of the string. and is the weight that hangs from one end of the string. Solve: (a) and L hasn’t changed, so l new 5 l l 5 2 L F T v 5 " F T / m . v 5 f l l 5 2 L , 0.50 1.00 0.33 Sum 370Hz 1110Hz 740Hz Displacement 1.0 2.0 t 1 ms 2 T 5 0.901 3 10 2 3 s. f 5 1110 Hz, T 5 1.35 3 10 2 3 s f 5 740 Hz, T 5 2.70 3 10 2 3 s f 5 370 Hz, T 5 1 / f 1.0 2.0 Time 1 ms 2 0.5 1.0 Displacement Sum 440Hz 880Hz 12-6 Chapter 12...
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