12_InstSolManual_PDF_Part15 - f L 5 1 v 1 v L v 1 v S 2 f S...

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Solve: (a) The approach of the two birds raises the frequency. (b) One canary hears a frequency of 2350 Hz and the waves move past it at so the wavelength it detects is For a stationary bird, The motion of the source toward the listener decreases the wavelength. 12.59. Set Up: The positive direction is from the listener to the source. (a) The wall is the listener. (b) The wall is the source and the car is the listener. Solve: (a) (b) Reflect: Since the singer and wall are moving toward each other the frequency received by the wall is greater than the frequency sung by the soprano, and the frequency she hears from the reflected sound is larger still. 12.60. Set Up: To treat the reflection of the waves use Problem-Solving Strategy 3 in Section 12.12. Solve: (a) First consider the truck as the listener, as shown in Figure 12.60a. Figure 12.60 f L
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Unformatted text preview: f L 5 1 v 1 v L v 1 v S 2 f S 5 1 344 m / s 2 20.0 m / s 344 m / s 2 30.0 m / s 2 1 2000 Hz 2 5 2064 Hz L S 30.0 m / s 20.0 m / s f S 5 1572 Hz ( b ) L 20.0 m / s f S 5 2000 Hz ( a ) North 1 1 S 30.0 m / s f L 5 1 v 1 v L v 1 v S 2 f S . f L 5 1 v 1 v L v 1 v S 2 f S 5 1 344 m / s 1 30 m / s 344 m / s 2 1 600 Hz 2 5 652 Hz f S 5 1 v 1 v S v 1 v L 2 f L 5 1 344 m / s 2 30 m / s 344 m / s 2 1 600 Hz 2 5 548 Hz f L 5 1 v 1 v L v 1 v S 2 f S . f S 5 600 Hz. v L 5 1 30 m / s. v S 5 0. f L 5 600 Hz. v L 5 0. v S 5 2 30 m / s. l 5 344 m / s 1750 Hz 5 0.197 m. l 5 344 m / s 1 15 m / s 1910 Hz 5 0.188 m. 344 m / s 1 15 m / s, f L 5 1 v 1 v L v 1 v S 2 f S 5 1 344 m / s 1 15.0 m / s 344 m / s 2 15.0 m / s 2 1 1750 Hz 2 5 1910 Hz v L 5 1 15.0 m / s v S 5 2 15.0 m / s, f S 5 1750 Hz, Mechanical Waves and Sound 12-15...
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