12_InstSolManual_PDF_Part22 - 12-22 Chapter 12 whale...

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whale transmits the sound: Reflect: The speed of the whale is much less than the speed of the waves and the fractional shift in frequency is very small. 12.76. Set Up: In one octave the frequency doubles. Solve: solve for x . and This person can hear about 10 octaves. 12.77. Set Up: The distance between crests is In front of the source and behind the source Solve: (a) and gives (b) Reflect: If the duck was held at rest but still paddled its feet, it would produce waves of wavelength In front of the duck the wavelength is decreased and behind the duck the wavelength is increased. The speed of the duck is 78% of the wave speed, so the Doppler effects are large. 12.78. Set Up: Take the positive direction to be from the listener to the source. For reflection off the bottom of the well the water surface first serves as a listener and then as a source. Solve: so the speed of the siren just before it hits the water is (a) The situation is shown in Figure 12.78a. Figure 12.78
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Unformatted text preview: f L 5 1 v v 1 49.5 m / s 2 f S 5 1 344 m / s 344 m / s 1 49.5 m / s 2 1 2500 Hz 2 5 2186 Hz ( b ) ( a ) v 5 L S 49.5 m / s 1 f S 5 2500 Hz 49.5 m / s v 5 L 1 S f S 5 2500 Hz " 2 1 9.80 m / s 2 21 125 m 2 5 49.5 m / s. v y 2 5 v y 2 1 2 a y 1 y 2 y 2 f L 5 1 v 1 v L v 1 v S 2 f S . l 5 0.32 m / s 0.625 Hz 5 0.51 m. l 5 v 1 v S f S 5 0.32 m / s 1 0.25 m / s 0.625 Hz 5 0.91 m v S 5 v 2 l f S 5 0.32 m / s 2 1 0.12 m 21 0.625 Hz 2 5 0.25 m / s. l 5 v 2 v S f S f S 5 1 / T 5 0.625 Hz. T 5 1.6 s v 1 v S f S . l 5 l 5 v 2 v S f S l . x 5 10 x ln 2 5 ln 1000 20 3 10 3 Hz 20 Hz 5 1000 5 2 x , D f 5 f L2 2 f S 5 1 v 1 v whale v 2 v whale 2 1 2 f S 5 1 2 v whale v 2 v whale 2 f S 5 1 2 3 4.95 m / s 4 1482 m / s 2 4.95 m / s 2 1 22.0 3 10 3 Hz 2 5 147 Hz f L2 5 1 v v 2 v whale 21 v 1 v whale v 2 f S 5 1 v 1 v whale v 2 v whale 2 f S . f L2 5 f L . f S 5 f S2 5 f L1 . v L 5 0. v S 5 2 v whale , 12-22 Chapter 12...
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