14_InstSolManual_PDF_Part17

# 14_InstSolManual_PDF_Part17 - Temperature and Heat 14-17...

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14.90. Set Up: so the sphere with twice the mass has twice the volume, For a sphere, and Solve: so and 14.91. Set Up: The radius of the earth is Since an ocean depth of 100 m is much less than the radius of the earth, we can calculate the volume of the water to this depth as the surface area of the oceans times 100 m. The total surface area of the earth is The density of seawater is (Table 13.1). Solve: The surface area of the oceans is The total rate of solar energy incident on the oceans is 12 hours per day for 30 days is so the total solar energy input to the oceans in one month is The volume of the seawater absorbing this energy is The mass of this water is so Reflect: A temperature rise of is significant. The solar energy input is a very large number, but so is the total mass of the top 100 m of seawater in the oceans. 3.4 C° D T 5 Q mc 5 4.65 3 10 23 J 1 3.51 3 10 19 kg 21 3890 J
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Unformatted text preview: / kg # C° 2 5 3.4 C° Q 5 mc D T , 1 3.41 3 10 16 m 3 2 5 3.51 3 10 19 kg. m 5 r V 5 1 1.03 3 10 3 kg / m 3 2 1 100 m 21 3.41 3 10 14 m 2 2 5 3.41 3 10 16 m 3 . 1 1.30 3 10 6 s 21 3.58 3 10 17 W 2 5 4.65 3 10 23 J. 1 12 21 30 21 3600 2 s 5 1.30 3 10 6 s, 1 1050 W / m 2 21 3.41 3 10 14 m 2 2 5 3.58 3 10 17 W. 1 2 / 3 2 A earth 5 1 2 / 3 21 4 p 21 6.38 3 10 6 m 2 2 5 3.41 3 10 14 m 2 . 1.03 3 10 3 kg / m 3 A earth 5 4 p R E 2 . R E 5 6.38 3 10 6 m. H L 5 A L e s T 4 5 2 2 / 3 A S e s T 4 5 2 2 / 3 H S 5 1.59 H S . H S 5 A S e s T 4 . A L 5 4 p 1 3 / 4 p 2 2 / 3 V L 2 / 3 5 4 p 1 3 / 4 p 2 2 / 3 1 2 V S 2 2 / 3 5 2 2 / 3 A S A S 5 4 p 1 3 / 4 p 2 2 / 3 V S 2 / 3 A 5 4 p 1 3 / 4 p 2 2 / 3 V 2 / 3 . r 5 1 3 V / 4 p 2 1 / 3 A 5 4 p r 2 . V 5 4 3 p r 3 V L 5 2 V S . m 5 r V Temperature and Heat 14-17...
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• Spring '07
• Shoberg
• Mass, Heat, #, 1 100 m, 1 1050 W, 2 1 3890 J, 4.65 3 1023 J

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