16_InstSolManual_PDF_Part3

16_InstSolManual_PDF_Part3 - 1 2 1 7.50 0.40 5 0.553 5...

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(b) Heat enters the gas in process ca , since T increases. (c) Heat leaves the gas in process bc , since T increases. (d) (e) Reflect: We did not use the number of moles of the gas. 16.10. Set Up: For the Otto cycle, R is the compression ratio. so is the fraction that is wasted. Solve: (a) and 23.8% is the fraction of the gasoline that produces waste heat. (b) For and 21.4% is wasted. 16.11. Set Up and Solve: and 16.12. Set Up: For a monatomic ideal gas and for a diatomic ideal gas Solve: The monatomic gas gives a larger e . For a monatomic gas, For a diatomic gas, 16.13. Set Up: Process is adiabatic. Solve: (a) (b) gives Reflect: In an adiabatic compression both the pressure and temperature increase. p b 5 1 T b T a 21 V a V b 2 p a 5 1 726 K 295 K 2 1 9.50 21 8.50 3 10 4 Pa 2 5 1.99 3 10 6 Pa. p a V a T a 5 p b V b T b . pV 5 nRT T b 5 T a 1 V a V b 2 g2 1 5 1 295 K 2 1 rV V 2 0.40 5 1 295 K 21 9.50 2 0.40 5 726 K 5 453°C. T a V a g2 1 5 T b V b g2 1 . T a 5 295 K. a S b e 5
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Unformatted text preview: 1 2 1 7.50 0.40 5 0.553 5 55.3%. e 5 1 2 1 7.50 0.67 5 0.741 5 74.1%. g 5 1.40. g 5 1.67 e 5 1 2 1 r g2 1 . r 5 13.8. r 0.40 5 1 0.350 1 r g2 1 5 1 2 e 5 0.350. e 5 1 2 1 r g2 1 . e 5 1 2 1 10.0 0.67 5 0.786 5 78.6% r 5 10.0, e 5 1 2 1 8.50 0.67 5 0.762 5 76.2% 1 2 e 5 Q C Q H e 5 W Q H 5 1 1 Q C Q H 5 1 2 Q C Q H e 5 1 2 1 r g2 1 . e 5 W Q H 5 1747 J 5470 J 5 0.319 5 31.9% W 5 Q H 1 Q C 5 1 5470 J 1 1 2 3723 J 2 5 1747 J Q C 5 2 3723 J Q 5 1 C p R 2 p D V 5 A 7 2 B1 1.5 atm 21 1.013 3 10 5 Pa / atm 21 2 7.0 3 10 2 3 m 3 2 5 2 3723 J Q H 5 5470 J Q 5 1 C V R 2 V D p 5 A 5 2 B1 2.0 3 10 2 3 m 3 21 12.3 atm 2 1.5 atm 21 1.013 3 10 5 Pa / atm 2 5 5470 J The Second Law of Thermodynamics 16-3...
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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