16_InstSolManual_PDF_Part13

# 16_InstSolManual_PDF_Part13 - The Second Law of...

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(b) process process process and process (c) is much larger. Reflect: This is equal to apart from a slight dif- ference due to rounding. For a cycle, since 16.50. Set Up: A person with surface area A and surface temperature radiates at a rate The person absorbs heat from the room at a rate where is the temperature of the room. In heat flows into the room and heat flows out of the room. The heat flows into and out of the room occur at a temperature of Solve: For the room, 16.51. Set Up: For a Carnot device, For the heat pump, and Solve: (a) (b) The natural gas would have to provide 13.2 J. 16.52. Set Up: For a Carnot device, is the magnitude of the heat delivered and is the amount of electrical energy used to operate the device. Solve: increases as becomes smaller. T H 2 T C 0 Q H 0 0 W 0 0 Q H 0 0 W 0 5 1 1 2 T C / T H 5 T H T H 2 T C . 0 W 0 0 Q H 0 e 5 0 W 0 0 Q H 0 5 1 2 T C T H . 0 Q H 0 5 0 W 0 1 2 T C / T H 5 1.00 J 1 2 1 268 K 2 / 1 290 K 2 5 13.2 J. 0 W 0 5 1.00 J. Q C . 0. Q H , 0 e 5 0 W 0 0 Q H 0 5 1 2 T C T H . T H 5 17.0°C 5 290 K. T C 5 2 5.0°C 5 268 K. D S 5 1 1.85 m 2 21 1.00 21 5.67 3 10 2 8 W / m 2 # K 4 21 1.0 213 303 K 4 4 2 3 293 K 4 4 2 293 K 5 0.379 J / K D S 5 Ae s tT 4 T s 2 Ae s tT s 4 T s 5 Ae s t 1 T 4 2 T s 4 2 T s T s . Ae s tT s 4 Ae s tT 4 t 5 1.0 s, T s 5 293 K H s 5 Ae s T s 4 , H 5 Ae s T 4 . T 5 303 K D U 5 0. W tot 5
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Unformatted text preview: 5 Q tot , W tot , Q tot 5 1 1422 J 1 1 2 1355 J 2 1 1 2 274 J 2 1 339 J 5 132 J. e Carnot e Carnot 5 1 2 T C T H 5 1 2 250 K 450 K 5 0.444 5 44.4%; e 5 W Q H 5 405 J 2 274 J 1422 J 1 339 J 5 0.0744 5 7.44%. Q 5 nC V D T 5 1 0.325 mol 21 20.85 J / mol # K 21 50 K 2 5 339 J. W 5 0. 4 S 1: Q 5 W 5 nRT 3 ln 1 V 4 V 3 2 5 1 0.325 mol 21 8.315 J / mol # K 21 250 K 2 ln 1 4.00 L 6.00L 2 5 2 274 J. D U 5 3 S 4: Q 5 nC V D T 5 1 0.325 mol 21 20.85 J / mol # K 21 2 200 K 2 5 2 1355 J. W 5 0. 2 S 3: Q 5 nC p D T 5 1 0.325 mol 21 29.17 J / mol # K 21 150 K 2 5 1422 J. W 5 p D V 5 nR D T 5 1 0.325 mol 21 8.315 J / mol # K 21 150 K 2 5 405 J. 1 S 2: n 5 p 1 V 1 RT 1 5 1 2.00 atm 21 4.00 L 2 1 0.08206 L # atm / mol # K 21 300 K 2 5 0.325 mol The Second Law of Thermodynamics 16-13...
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• Spring '07
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