16.56. Set Up: For water, Solve: (a) The heat that goes into the ice-water mixture is This is same amount of heat leaves the boiling water, so (b) (c) For any segment of the rod, the net heat flow is zero, so (d) 16.57. Set Up: ab is at constant pressure, bc is at constant volume, and ca is isothermal. For and For a constant pressure process, and so For a constant volume process, and so For an isothermal process, and Solve: (a) so heat enters the gas when pV increases. In an isothermal process heat leaves the gas when V decreases. So, in this cycle heat enters in process ab and leaves in processes bc and ca . (b) equals Q for process ab ,so For ab , For bc , For ca , The total work for the cycle is Reflect: For a cycle, and The total heat flow must be but in calculating e we use only the heat that flows into the engine. 16.58. Set Up: For a refrigerator, If the cycle is run in reverse, W has the same magnitude and opposite sign. Heat enters the refrigerator in processes ac and cb and leaves the refrigerator in process
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.