Unformatted text preview: 17.54. Set Up: Gauss’s law says Solve: (a) (b) 17.55. Set Up: Gauss’s law says that the net electric flux through any closed surface equals where is the net charge enclosed by the surface. Solve: so and and and and Reflect: The electric field varies in a complicated way, in both magnitude and direction, for each of the surfaces and direct calculation of the flux as would be very difficult. Gauss’s law gives us a very simple way of calcu- lating the net flux. 17.56. Set Up: The cube is a closed surface so we can apply Gauss’s law to it: By symmetry the flux is the same through each of the 6 faces of the cube. Solve: (a) The total flux through the cube is (b) The flux through each face is 17.57. Set Up: Example 17.10 shows that inside a uniform spherical shell and that outside the shell. Solve: (a) (b) and (c) and Reflect: Outside the shell the electric field is the same as if all the charge were concentrated at the center of the shell. But inside the shell the field is not the same as for a point charge at the center of the shell; inside the shell theshell....
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- Spring '07
- Charge, Electric charge, Qencl