17_InstSolManual_PDF_Part22

17_InstSolManual_PDF_Part22 - 4 1 3.00 3 10 2 16 2 2 C 5...

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Solve: (a) Since and are all in the direction, This gives and (b) Both and are in the direction, so is in the direction. (c) The forces and on in each of the three regions are sketched in Figure 17.65b. Only in regions I (to the left of ) and III (to the right of ) are and in opposite directions. But since must be closer to than to in order for and this is the case only in region I. Let be a distance d to the left of so it is a distance from gives The positive solution is This point is at Reflect: At the point found in part (c) the electric field is zero. The force on any charge placed at this point will be zero. 17.66. Set Up: Let and be the charges on the spheres. and Solve: so The quadratic formula gives or For and for One sphere has charge and the other has charge 17.67. Set Up: Like charges repel and unlike charges attract. The three charges and the forces on are shown in Figure 17.67. Figure 17.67 y x 0.050 m 0.030 m 0.040 m 1 1 F 1 y F 1 x F 2 q 2 q 3 q 1 F 1 2 u u q 3 F 5 k 0 qq r 0 r 2 . 5.45 3 10 2 8 C. 0.55 3 10 2 8 C q 2 5 0.55 3 10 2 8 C. q 1 5 5.45 3 10 2 8 C, q 2 5 5.45 3 10 2 8 C q 1 5 0.55 3 10 2 8 C, 5.45 3 10 2 8 C. q 1 5 1 2 1 6.00 3 10 2 8 6 "1 6.00 3 10 2 8 2 2 2
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Unformatted text preview: 4 1 3.00 3 10 2 16 2 2 C 5 0.55 3 10 2 8 C q 1 2 2 1 60.0 3 10 2 9 C 2 q 1 1 3.00 3 10 2 16 C 2 5 0. q 1 1 60.0 3 10 2 9 C 2 q 1 2 5 3.00 3 10 2 16 C 2 . q 2 5 60.0 3 10 2 9 C 2 q 1 q 1 q 2 5 Fr 2 k 5 1 0.270 3 10 2 3 N 21 0.100 m 2 2 8.99 3 10 9 N # m 2 / C 2 5 3.00 3 10 2 16 C 2 . q 1 1 q 2 5 60.0 nC. F 5 k q 1 q 2 r 2 q 2 q 1 x 5 2 0.300 m 2 1.46 m 5 2 1.76 m. d 5 1.46 m. " 1.80 d 5 6 1 d 1 0.500 m 2 . 1.80 d 2 5 1 d 1 0.500 m 2 2 . k 4.50 nC 1 d 1 0.500 m 2 2 5 k 2.50 nC d 2 . F 1 5 F 2 q 1 . d 1 0.500 m q 2 , q 3 F 1 5 F 2 , q 1 q 2 q 3 q 2 , q 1 , F S 2 F S 1 q 1 q 2 q 3 F S 2 F S 1 1 x F S net 5 F S 1 1 F S 2 1 x F S 2 F S 1 q 3 5 3.17 3 10 2 9 C 5 3.17 nC. 4.00 3 10 2 6 N 8.99 3 10 9 N # m 2 / C 2 5 q 3 1 4.50 3 10 2 9 C 3 0.200 m 4 2 1 2.50 3 10 2 9 C 3 0.300 m 4 2 2 4.00 3 10 2 6 N 5 k q 1 q 3 r 1 2 1 k q 2 q 3 r 2 2 . F 5 F 1 1 F 2 . 1 x F S net F S 2 F S 1 , 17-22 Chapter 17...
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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