17_InstSolManual_PDF_Part23

17_InstSolManual_PDF_Part23 - 3 10 2 5 N. F x 5 F 1 x 1 F 2...

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Solve: (a) (b) below the axis. Reflect: The individual forces on are computed from Coulomb’s law and then added as vectors, using components. 17.68. Set Up: Like charges repel and unlike charges attract. The positions of the three charges are sketched in Figure 17.68a and each force on is shown. The distance between and is 5.00 cm. Figure 17.68 Solve: (a) F y 5 F 1 y 1 F 2 y 52 4.32 3 10 2 5 N F x 5 F 1 x 1 F 2 x 5 9.989 3 10 2 5 N 1 1 2 3.236 3 10 2 5 N 2 5 6.75 3 10 2 5 N; F 2 y 5 0 F 2 x 5 9.989 3 10 2 5 N; F 2 5 k 0 q 2 q 3 0 r 2 2 5 1 8.99 3 10 9 N # m 2 / C 2 2 1 2.00 3 10 2 9 C 21 5.00 3 10 2 9 C 2 1 3.00 3 10 2 2 m 2 2 5 9.989 3 10 2 5 N F 1 y 52 F 1 sin u52 1 5.394 3 10 2 5 N 21 0.800 2 52 4.315 3 10 2 5 N F 1 x 52 F 1 cos u52 1 5.394 3 10 2 5 N 21 0.600 2 52 3.236 3 10 2 5 N; F 1 5 k 0 q 1 q 3 0 r 1 2 5 1 8.99 3 10 9 N # m 2 / C 2 2 1 3.00 3 10 2 9 C 21 5.00 3 10 2 9 C 2 1 5.00 3 10 2 2 m 2 2 5 5.394 3 10 2 5 N x y u u F 1 F 1 x F 1 y F 2 q 2 q 3 q 1 5.0cm 4.0cm (a) y x u F F x F y (b) 1 2 1 q 3 q 1 q 3 F 5 k 0 q 1 q 2 0 r 2 . q 3 1 x f5 32.6°, tan f5 P F y F x P 5 0.640. F 5 " F x 2 1 F y 2 5 1.02 3 10 2 4 N. F y 5 F 1 y 1 F 2 y 5 6.48 3 10 2 5 N 1 1 2 1.20 3 10 2 4 N 2 52 5.52
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Unformatted text preview: 3 10 2 5 N. F x 5 F 1 x 1 F 2 x 5 8.63 3 10 2 5 N. F 2 y 5 2 F 2 5 2 1.20 3 10 2 4 N. F 2 x 5 0, F 2 5 k q 2 q 3 r 2 2 5 1 8.99 3 10 9 N # m 2 / C 2 2 1 2.00 3 10 2 9 C 21 6.00 3 10 2 9 C 2 1 0.0300 m 2 2 5 1.20 3 10 2 4 C. F 1 y 5 1 F 1 sin u 5 6.48 3 10 2 5 N. F 1 x 5 1 F 1 cos u 5 8.63 3 10 2 5 N. u 5 36.9. F 1 5 k q 1 q 3 r 1 2 5 1 8.99 3 10 9 N # m 2 / C 2 2 1 5.00 3 10 2 9 C 21 6.00 3 10 2 9 C 2 1 0.0500 m 2 2 5 1.079 3 10 2 4 C. Electric Charge and Electric Field 17-23...
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