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17_InstSolManual_PDF_Part26

# 17_InstSolManual_PDF_Part26 - We could also do this problem...

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17.74. Set Up: The force diagram for the charge is given in Figure 17.74. is the force exerted on the charge by the uniform electric field. The charge is negative and the field is to the right, so the force exerted by the field is to the left. is the force exerted by the other point charge. The two charges have opposite signs, so the force is attractive. Take the axis to be to the right, as shown in the figure. Figure 17.74 Solve: (a) gives and (b) Now is to the left, since like charges repel. gives and 17.75. Set Up: The force on the electron is upward in the figure so the electric field must be downward. To produce a net electric field that is downward, it must be that is positive, is negative and The field due to and at the location of the electron are sketched in Figure 17.75. The electron is from each charge. and Figure 17.75 Solve: The net electric field is so and Reflect: The force that an electric field exerts on a negative charge is opposite to the direction of the electric field.
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Unformatted text preview: We could also do this problem by considering the force that each charge exerts on the electron. q 2 5 2 6.14 3 10 2 6 C. q 1 5 r 2 ma 2 ke cos u 5 1 3.61 3 10 2 2 m 2 2 1 9.11 3 10 2 31 kg 21 8.25 3 10 18 m / s 2 2 2 1 8.99 3 10 9 N # m 2 / C 2 21 1.60 3 10 2 19 C 2 cos 56.3° 5 6.14 3 10 2 6 C. 2 keq 1 r 2 cos u 5 ma F 5 ma F 5 eE 5 2 keq 1 r 2 cos u . E 5 2 E 1 y 5 2 k q 1 r 2 cos u . x y q 2 1 E x y r 2.0cm 3.0cm u u u u 5 56.3°. tan u 5 3.00 cm 2.00 cm r 5 3.61 cm q 2 q 1 q 1 5 q 2 . q 2 q 1 T 5 F E 1 F q 5 2.02 3 10 3 N. T 2 F q 2 F E 5 a F x 5 F q T 5 F E 2 F q 5 382 N. T 1 F q 2 F E 5 a F x 5 F q 5 k q 1 q 2 r 2 5 1 8.99 3 10 9 N # m 2 / C 2 2 1 6.50 3 10 2 6 C 21 8.75 3 10 2 6 C 2 1 0.0250 m 2 2 5 8.18 3 10 2 N F 5 q E 5 1 6.50 3 10 2 6 C 21 1.85 3 10 8 N / C 2 5 1.20 3 10 3 N y T x F q F E E 1 x F q F E 2 6.50 m C 17-26 Chapter 17...
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