18_InstSolManual_PDF_Part9 - Electric Potential and...

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Solve: (a) electron: proton: (b) electron: proton: (c) The proton energy is larger by a factor of Reflect: When we use we should express all quantities in SI units. 18.36. Set Up: Solve: (a) (b) 18.37. Set Up: and Solve: 18.38. Set Up: For a parallel-plate capacitor, and Solve: (a) (b) (c) 18.39. Set Up: For a parallel-plate capacitor The surface charge density is Solve: (a) (b) (c) (d) Reflect: If the plates are square, each side is about 18 cm in length. We could also calculate from 18.40. Set Up: when there is air between the plates. Solve: 18.41. Set Up: Solve: (a) (b) When d is doubled C is halved, so Q is halved. Q 5 60 m C. Q 5 CV ab 5 1 10.0 3 10 2 6 F 21 12.0 V 2 5 1.20 3 10 2 4 C 5 120 m C C 5 P 0 A d . C 5 Q V ab . C 5 1 8.854 3 10 2 12 F / m 21 3.0 3 10 2 2 m 2 2 5.0 3 10 2 3 m 5 1.59 3 10 2 12 F 5 1.59 pF C 5 P 0 A d E 5 s / P 0 . s s 5 Q A 5 0.200 3 10 2 6 C 0.0339 m 2 5 5.90 3 10 2 6 C / m 2 E 5 V ab d 5 400 V 0.600 3 10 2 3 m 5 6.67 3 10 5 V / m A 5 Cd P 0 5 1 500.0 3 10 2 12 F 21 0.600 3 10 2 3 m 2 8.854 3 10 2 12 C 2 / 1 N # m 2 2 5 0.0339 m 2 V ab 5 Q C 5 0.200 3 10 2 6 C 500.0 3 10 2 12 F 5 400 V s 5 Q A . V ab 5 Ed . C 5 P 0 A d . C 5 Q V ab . C 5 Q V ab 5 80.0 3 10 2 9 C 1.00 3 10 4 V 5 8.00 3 10 2 12 F 5 8.00 pF A 5 Q E P 0 5 80.0 3 10 2 9 C 1 4.00 3 10 6 V / m 21 8.854 3 10 2 12 C 2 / 1 N # m 2 2 5 2.26 3 10 2 3 m 2 5 22.6 cm 2 V ab 5 Ed 5 1 4.00 3 10 6 V / m 21 2.50 3 10 2 3 m 2 5 1.00 3 10 4 V C 5 Q V ab . E 5 Q P 0 A V ab 5 Ed , 1 F 5 1 1 C 2 N # m 21 1 N 1 kg # m / s 2 2 5 C 2 # s 2 kg # m 2 1 N 5 1 kg # m / s 2 . 1 F 5 1 C 2 / N # m
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