18.51.Set Up:In parallel, the potential difference is the same for each capacitor and is equal to the appliedpotential difference. Solve: (a)and (b)The potential difference across each capacitor is 48.0 V. For the capacitor,For the capacitor,18.52.Set Up:In series, the charges on the capacitors are the same and the sum of the potential differences acrossthe capacitors is the applied potential difference. Let and Solve: (a)The charge on each capacitor is (b)The potential difference across the capacitor is 28.8 V and the potential difference across the capac-itor is 19.2 V.18.53.Set Up:For two capacitors in parallel,For two capacitors in series,and For capacitors in parallel, the voltages are the same and the charges add. For capacitors in series, the charges are thesame and the voltages add. Let and Figure 18.53Solve: (a)The equivalent capacitance for and in parallel is This gives the circuitshown in Figure 18.53a. In that circuit the equivalent capacitance is This gives the circuit shown in Figure 18.53b. In Figure 18.53b,In Figure 18.53a each capacitor therefore has charge
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