18_InstSolManual_PDF_Part17 - Electric Potential and...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
(b) From Figure 18.66c, From Figure 18.66b, This one capacitor stores nearly half the total stored energy. 18.67. Set Up: For a parallel-plate capacitor, Solve: (a) U is proportional to so increase the charge by a factor of to double the stored energy. We didn’t use so this result applies to any capacitor. (b) Still connected to the battery means V stays constant and Q changes. means (c) goes to so Reflect: In parts (b) and (c) the change causes the charge on the capacitor to increase and this increases the electric field between the plates and therefore increases the stored energy. 18.68. Set Up: The field when there is air between the plates is The field when the dielectric is between the plates is Solve: 18.69. Set Up: for a parallel plate capacitor; this equation applies whether or not a dielectric is present. Solve: (a) per (b) Reflect: The dielectric material increases the capacitance and decreases the electric field that corresponds to a given potential difference. 18.70. Set Up:
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online