18_InstSolManual_PDF_Part18

# 18_InstSolManual_PDF_Part18 - 18-18 Chapter 18 18.72 Set Up...

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18.72. Set Up: The capacitance with the dielectric present is The dielectric strength is the maximum allowed field between the plates. Solve: (a) (b) 18.73. Set Up: Solve: 18.74. Set Up: The potential of a point charge is Figure 18.74 Solve: (a) The positions of the two charges are shown in Figure 18.74. (b) Any point on the x axis is the same distance from each charge, so The potential is zero at all points on the x axis. 18.75. Set Up: For a point charge, and The electric field is directed toward a negative charge and away from a positive charge. Solve: (a) so (b) (c) so the electric field is directed away from the charge. Reflect: The ratio of V to E due to a point charge increases as the distance r from the charge increases, because E falls off as and V falls off as 18.76. Set Up: The charge of the alpha particle is and the charge of the radon nucleus is Solve: (a) The final energy of the alpha particle, 4.79 MeV, equals the electrical potential energy of the alpha-radon
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Unformatted text preview: combination just before the decay. (b) r 5 kqq r U 5 1 8.99 3 10 9 N # m 2 / C 2 21 2 21 86 21 1.60 3 10 2 19 C 2 2 7.66 3 10 2 13 J 5 5.17 3 10 2 14 m U 5 4.79 MeV 5 7.66 3 10 2 13 J. 1 86 e . 1 2 e U a 1 K a 5 U b 1 K b . U 5 k qq r r . 1 / r . 1 / r 2 q . 0, q 5 rV k 5 1 0.415 m 21 4.98 V 2 8.99 3 10 9 N # m 2 / C 2 5 2.30 3 10 2 10 C r 5 4.98 V 12.0 V / m 5 0.415 m. V E 5 kq / r k q / r 2 5 1 kq r 21 r 2 kq 2 5 r . q . 0. V . V 5 kq r . E 5 k q r 2 V 5 kq r 1 k 1 2 q 2 r 5 0. y x P 1 q 2 q V 5 kq r . K 5 E E 5 3.20 3 10 5 V / m 2.50 3 10 5 V / m 5 1.28. E 5 E K . V ab 5 1 2 1 50.0 3 10 6 V / m 21 0.0800 3 10 2 3 m 2 5 2.00 3 10 3 V A 5 Cd K P 5 1 0.200 3 10 2 6 F 21 0.0800 3 10 2 3 m 2 1 2.50 21 8.854 3 10 2 12 C 2 / 1 N # m 2 22 5 0.723 m 2 V ab 5 Ed . C 5 KC 5 K P A d . 18-18 Chapter 18...
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