19_InstSolManual_PDF_Part9 - circuit shown in Figure 19.48...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
19.47. Set Up: A network of N of the resistors in series has resistance and a network of N of the resistors in parallel has resistance Solve: (a) A parallel combination of two resistors in series with three others (Figure 19.47a). (b) Ten in parallel. (c) Three in parallel. (d) Two in parallel in series with four in parallel (Figure 19.47b). Figure 19.47 Reflect: There are other networks that also have the required resistance. An important additional consideration is the power dissipated by each resistor, whether the power dissipated by any resistor in the network exceeds the maximum power rating of the resistor. 19.48. Set Up: so the resistance is proportional to the length of the bar. The bars can be represented by the
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: circuit shown in Figure 19.48. Figure 19.48 Solve: The two resistors in parallel have an equivalent resistance Then the three resistors in series have equivalent resistance 19.49. Set Up: For a parallel connection the full line voltage appears across each resistor. The equivalent resistance is and R eq 5 R 1 R 2 R 1 1 R 2 . 1 R eq 5 1 R 1 1 1 R 2 R 5 2 R 3 1 R 6 1 2 R 3 5 9 R 6 5 3 R 2 . 1 R / 3 2 2 5 R 6 . R / 3 R / 3 2 R / 3 2 R / 3 R 5 r L A 10.0 V 10.0 V 10.0 V 10.0 V 10.0 V ( a ) 10.0 V 10.0 V 10.0 V 10.0 V 10.0 V 10.0 V ( b ) 1 10.0 V 2 / N . N 1 10.0 V 2 Current, Resistance, and Direct-Current Circuits 19-9...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern