19_InstSolManual_PDF_Part9

19_InstSolManual_PDF_Part9 - circuit shown in Figure 19.48....

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19.47. Set Up: A network of N of the resistors in series has resistance and a network of N of the resistors in parallel has resistance Solve: (a) A parallel combination of two resistors in series with three others (Figure 19.47a). (b) Ten in parallel. (c) Three in parallel. (d) Two in parallel in series with four in parallel (Figure 19.47b). Figure 19.47 Reflect: There are other networks that also have the required resistance. An important additional consideration is the power dissipated by each resistor, whether the power dissipated by any resistor in the network exceeds the maximum power rating of the resistor. 19.48. Set Up: so the resistance is proportional to the length of the bar. The bars can be represented by the
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Unformatted text preview: circuit shown in Figure 19.48. Figure 19.48 Solve: The two resistors in parallel have an equivalent resistance Then the three resistors in series have equivalent resistance 19.49. Set Up: For a parallel connection the full line voltage appears across each resistor. The equivalent resistance is and R eq 5 R 1 R 2 R 1 1 R 2 . 1 R eq 5 1 R 1 1 1 R 2 R 5 2 R 3 1 R 6 1 2 R 3 5 9 R 6 5 3 R 2 . 1 R / 3 2 2 5 R 6 . R / 3 R / 3 2 R / 3 2 R / 3 R 5 r L A 10.0 V 10.0 V 10.0 V 10.0 V 10.0 V ( a ) 10.0 V 10.0 V 10.0 V 10.0 V 10.0 V 10.0 V ( b ) 1 10.0 V 2 / N . N 1 10.0 V 2 Current, Resistance, and Direct-Current Circuits 19-9...
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