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19_InstSolManual_PDF_Part10 - 19-10 Chapter 19 1 40.0 V 2 1...

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Solve: (a) (b) (c) For the resistor, For the resistor, Reflect: If either resistor is removed, the voltage and current for the other resistor is unchanged. 19.50. Set Up: Let For a parallel network the full battery voltage appears across each resistor. The equivalent resistance is given by Solve: (a) and (b) (c) This is also equal to (d) The voltage is 28.0 V across each resistor. (e) (f) Since and V is the same for all three resistors, the resistor with the smallest R dissipates the greatest power. 19.51. Set Up: Let For a series network, the current is the same in each resistor and the sum of voltages for each resistor equals the battery voltage. The equivalent resistance is Solve: (a) (b) (c) the same as for each resistor. (d) Note that (e) (f) Since and the current is the same for each resistor, the resistor with the greatest R dissipates the greatest power. Reflect: When resistors are connected in parallel, the resistor with the smallest R dissipates the greatest power.
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