This preview shows page 1. Sign up to view the full content.
Solve: (a)
Replacing series and parallel combinations of resistors by their equivalents gives the equivalent networks
as shown in Figure 19.86. The equivalent resistance of the network is
Figure 19.86
(b)
The voltage across the
resistor in Figure 19.86a is
This is the voltage across
the
resistor in Figure 19.86b. The current through the
resistor is 4.8 A. This is also the current through
the
resistor and the voltage across that resistor is 96.0 V. Therefore, the voltage between points
x
and
y
is
This voltage is divided equally between the
resistors in Figure 19.86b, so the
voltage between points
x
and
y
is
The voltmeter will read 57.6 V.
19.87. Set Up:
Table 19.1 gives the resistivities of copper and aluminum to be
and
For the cables in series (endtoend),
For the cables in parallel the
equivalent resistance
is given by
Note that in the two configurations the copper and aluminum
sections have different lengths. And, for the parallel cables the cross sectional area of each cable is half what it is for
the end to end configuration.
This is the end of the preview. Sign up
to
access the rest of the document.
 Spring '07
 Shoberg
 Resistance, Work

Click to edit the document details