19_InstSolManual_PDF_Part24

19_InstSolManual_PDF_Part24 - a and d is so and Using these...

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The voltmeter reads 0.22 V. is positive, so point a is at higher potential. Reflect: Since there is no current in the middle branch, the two resistances in that branch could be removed without affecting the potential difference The 10.0 V emf doesn’t affect the current but does affect 19.90. Set Up: The charge is reduced to of its maximum value when Solve: (a) At (b) 19.91. Set Up: At Solve: (a) At and (b) so 19.92. Set Up: Zero current through the galvanometer means the current through N is also the current through M and the current through P is the same as the current through X . And it means that points b and c are at the same potential, so Solve: (a) The voltage between points
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Unformatted text preview: a and d is so and Using these expressions in gives and (b) X 5 MP N 5 1 850.0 V 21 33.48 V 2 15.00 V 5 1897 V X 5 MP / N . NX 5 PM N 1 P 1 X 2 5 P 1 N 1 M 2 . E N 1 M N 5 E P 1 X P . I 1 N 5 I 2 P I 2 5 E P 1 X . I 1 5 E N 1 M E , I 1 N 5 I 2 P . I 2 I 1 C 5 t R 5 6.00 s 5.00 3 10 5 V 5 1.20 3 10 2 5 F. t 5 RC R 5 E i 5 400.0 V 0.800 3 10 2 3 A 5 5.00 3 10 5 V . E 5 iR t 5 0, t 5 RC . q 5 0. t 5 0, E 5 iR 1 q C . t 5 t 5 1 4600 V 21 0.800 3 10 2 9 F 2 5 3.68 3 10 2 6 s 5 3.68 m s. q 5 iRC 5 1 0.250 A 21 4600 V 21 0.800 3 10 2 9 F 2 5 9.20 3 10 2 7 C 5 0.920 m C. t 5 0, t 5 t 5 RC . 1 / e iR 5 q C . V ab V ab . V a 2 V b 19-24 Chapter 19...
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