20_InstSolManual_PDF_Part28

# 20_InstSolManual_PDF_Part28 - 20-28 Chapter 20 20.96 Set Up...

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20.96. Set Up: Label the three segments in the magnetic field 1, 2, and 3, as shown in Figure 20.96a. The force on a current carrying conductor is where is the angle between the direction of the current and the direction of the magnetic field. The direction of the force on each segment is given by the right-hand rule and is shown in the figure. The sum of and is the same as the force on a wire 0.307 m long. Section 2 has length 0.800 m. The current in each segment is perpendicular to the magnetic field, so Figure 20.96 Solve: The forces and a coordinate system are shown in Figure 20.96b. has been resolved into its x and y components. and the resultant total force are shown in Figure 20.96c. The resultant force has magnitude 1.97 N and is at 68.3° clockwise from the left-hand straight segment. 20.97. Set Up: Conservation of energy relates the accelerating potential difference
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## This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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