21.56.Set Up:Problem 21.55 shows that initially is zero and rises to 25.0 V, that starts at 25.0 V anddecreases to zero, and that istarts at zero and rises to 1.67 A. so is proportional to i. Areads the current i.Solve:The graphs are sketched in Figure 21.56.Figure 21.5621.57.Set Up:Current decay in an R-Lcircuit is described by Eq. (21.28). Solve:and and Reflect:As Ris decreased the time constant increases and it takes longer for the current to decay. For this circuit thetime constant isAfter one time constant the current has decayed to about 37% of its original value.It is reasonable for it to take a little over two time constants for the current to decay to 10% of its original value.21.58.Set Up:The current as a function of time is given by The energy stored in the inductor is Ureaches its maximum value when iis times its maximum value.Solve: (a)The maximum current is gives and (b)and 21.59.Set Up:The resonant angular frequency of an L-Ccircuit is Solve:21.60.
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