21_InstSolManual_PDF_Part14

21_InstSolManual_PDF - 21-14 Chapter 21 E 5 vBL where v is the component of velocity perpendicular to the eld direction and perpendicular to the

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21.61. Set Up: Wires A and C have a length of 0.500 m and wire D has a length of where v is the component of velocity perpendicular to the field direction and perpendicular to the bar. Solve: (a) is parallel to so the induced emf is zero. (b) is perpendicular to The component of perpendicular to the bar is (c) is perpendicular to The component of perpendicular to the bar is Reflect: The induced emf depends on the angle between and and also on the angle between and the bar. 21.62. Set Up: The energy stored in a capacitor is The energy stored in an inductor is Energy conservation requires that the total stored energy be constant. The current is a maximum when the charge on the capacitor is zero. Solve: (a) At this instant (b) At this instant (c) This is when 21.63. Set Up: Use to find the amount of heat energy that must go into the water. The energy stored in an inductor is Solve: This much energy must be stored in the inductor, so This is a huge current; not reasonable for ordinary inductors. Reflect:
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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