22_InstSolManual_PDF_Part4

22_InstSolManual_PDF_Part4 - f 5 X L R 5 100 V 200 V V L 5...

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22.10. Set Up: and Solve: (a) The voltage amplitude V is the maximum voltage so (b) 22.11. Set Up: With no capacitor, and and For an inductor, the voltage leads the current. Solve: (a) (b) (c) (d) and Since is positive, the source voltage leads the current. (e) The phasor diagram is sketched in Figure 22.11. Figure 22.11 Reflect: Note that is greater than V. The loop rule is satisfied at each instance of time but the voltages across R and L reach their maxima at different times. V R 1 V L V V R V L I f f f51 26.6°. tan
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Unformatted text preview: f 5 X L R 5 100 V 200 V V L 5 IX L 5 1 0.134 A 21 100 V 2 5 13.4 V. V R 5 IR 5 1 0.134 A 21 200 V 2 5 26.8 V. I 5 V Z 5 30.0 V 224 V 5 0.134 A Z 5 "1 200 V 2 2 1 1 100 V 2 2 5 224 V . X L 5 v L 5 1 250 rad / s 21 0.400 H 2 5 100 V . V R 5 IR . V L 5 IX L I 5 V Z . X L 5 v L . tan f 5 X L R . Z 5 " R 2 1 X L 2 V rms 5 V " 2 5 12.0 V " 2 5 8.48 V " 2 1 7.50 mA 2 5 10.6 mA. I 5 " 2 I rms 5 V 5 12.0 V. V rms 5 V / " 2 . I rms 5 I / " 2 22-4 Chapter 22...
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