22_InstSolManual_PDF_Part5

# 22_InstSolManual_PDF_Part5 - Alternating Current 22-5 22.12...

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22.12. Set Up: With no inductor, and For a capacitor, the voltage lags the current. Solve: (a) (b) (c) (d) and Since is negative, the source voltage lags the current. (e) The phasor diagram is sketched in Figure 22.12. Figure 22.12 Figure 22.13 22.13. Set Up: With no resistor, For an inductor, the voltage leads the current. For a capacitor, the voltage lags the current. Solve: (a) (b) (c) (d) and The phase angle is negative and the source volt- age lags the current. (e) The phasor diagram is sketched in Figure 22.13. Reflect: When the phase angle is negative and the source voltage lags the current. X C . X L f 5 2 90°. tan f 5 X L 2 X C zero 5 100 V 2 667 V zero 5 2` V L 5 IX L 5 1 0.0529 A 21 100 V 2 5 5.29 V. V C 5 IX C 5 1 0.0529 A 21 667 V 2 5 35.3 V. I 5 V Z 5 30.0 V 567 V 5 0.0529 A Z 5 0 X L 2 X C 0 5 0 100
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Unformatted text preview: 100 V 2 667 V 5 567 V . X C 5 1 v C 5 1 1 250 rad / s 21 6.00 3 10 2 6 F 2 5 667 V . X L 5 v L 5 1 250 rad / s 21 0.400 H 2 5 100 V . X L 5 v L . X C 5 1 v C . tan f 5 X L 2 X C zero . Z 5 "1 X L 2 X C 2 2 5 X L 2 X C . V L V C V I f V R V C V f I f f 5 2 73.3°. tan f 5 2 X C R 5 2 667 V 200 V V C 5 IX C 5 1 0.0431 A 21 667 V 2 5 28.7 V. V R 5 IR 5 1 0.0431 A 21 200 V 2 5 8.62 V. I 5 V Z 5 30.0 V 696 V 5 0.0431 A Z 5 "1 200 V 2 2 1 1 667 V 2 2 5 696 V . X C 5 1 v C 5 1 1 250 rad / s 21 6.00 3 10 2 6 F 2 5 667 V . V R 5 IR . V C 5 IX C . I 5 V Z . X C 5 1 v C . tan f 5 2 X C R . Z 5 " R 2 1 X C 2 Alternating Current 22-5...
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• Spring '07
• Shoberg

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