22_InstSolManual_PDF_Part16

22_InstSolManual_PDF_Part16 - I rms 5 V rms R 5 110 V 5.87...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
22.41. Set Up: Solve: (a) (b) (c) or Reflect: The impedance of the circuit depends only on the absolute value of not on its sign. For the phase angle is positive and for the phase angle is negative. 22.42. Set Up: is the rate at which heat is generated. Solve: 22.43. Set Up: The power factor is unity when and Solve: (a) (b) so Need to add and (c) so Reflect: When the circuit is at resonance (when ), the current is a maximum and the power delivered by the source is a maximum. For any series circuit, the power delivered by the source equals the power consumed in the resistor. 22.44. Set Up: The voltage lags the current when and and Solve: (a) Since add an inductor to make (c) and gives Need to add so 22.45. Set Up: Solve: (a) (b) V rms 5 I rms Z 5 1 0.447 A 21 361 V 2 5 161 V cos f5 R Z 5 300 V 361 V 5 0.831. Z 5 "1 300 V 2 2 1 1 500 V2 300 V 2 2 5 361 V . I rms 5 Å P R 5 Å 60.0 W 300 V 5 0.447 A. V rms 5 I rms Z . Z 5 " R 2 1 1 X L 2 X C 2 2 . cos f5 R Z . P 5 I rms 2 R . L 5 X L 2 p f 5 30.0 V 2 p 1 60.0 Hz 2 5 0.0796 H. X L 5v L 5 2 p fL , X L 5 30.0 V . R tan f5 1 40.0 V 2 tan 1 2 36.9° 2 52 30.0 V . X L 2 X C 5 R 5 Z cos f5 1 50.0 V 21 0.800 2 5 40.0 V . cos f5 R Z f52 36.9°. cos f5 0.800 X C 5 X L . X C . X L , cos f5 R Z . tan f5 X L 2 X C R f, 0. X C . X L R - L - C X L 5 X C P 5 I rms 2 R 5 1 18.74 A 2 2 1 5.87 V 2 5 2060 W.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: I rms 5 V rms R 5 110 V 5.87 V 5 18.74 A. Z 5 R . X L 5 X C C 5 1 2 p f X C 5 1 2 p 1 60.0 Hz 21 13.4 V 2 5 1.98 3 10 2 4 F 5 0.198 mF. X C 5 1 2 p fC X C 5 13.4 V . X L 2 X C 5 R tan f 5 1 5.87 V 2 tan 66.4° 5 13.4 V . f 5 66.4°. cos f 5 0.400 R 5 P I rms 2 5 330 W 1 7.50 A 2 2 5 5.87 V . I rms 5 P V rms cos f 5 330 W 1 110 V 21 0.400 2 5 7.50 A. X L 5 X C . f 5 0° tan f 5 X L 2 X C R . P 5 V rms I rms cos f 5 I rms 2 R . Z 5 "1 64.0 V 2 2 1 1 25.0 V 2 2 5 68.7 V . R 5 P I rms 2 5 16.0 W 1 0.500 A 2 2 5 64.0 V . Z 5 " R 2 1 X L 2 . P 5 I rms 2 R X L 5 468 V X L 5 732 V X L 2 X C , 468 V . X L 5 732 V X L 5 X C 6 " Z 2 2 R 2 5 600 V 6 "1 200 V 2 2 2 1 150 V 2 2 5 600 V 6 132 V . X L 2 X C 5 6 " Z 2 2 R 2 . Z 2 5 R 2 1 1 X L 2 X C 2 2 . Z 5 V I 5 240 V 1.20 A 5 200 V I 5 V C X C 5 720 V 600 V 5 1.20 A Z 5 " R 2 1 1 X L 2 X C 2 2 . V 5 IZ . V C 5 IX C . 22-16 Chapter 22...
View Full Document

This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

Ask a homework question - tutors are online