PHYS
23_InstSolManual_PDF_Part8

# 23_InstSolManual_PDF_Part8 - 23-8 Chapter 23 23.29 Set Up...

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23.29. Set Up: The two rays are shown in Figure 23.29. The two angles labeled are equal because of the law of reflection. The angle between the two reflected rays is Figure 23.29 Solve: and since the lines forming one angle are parallel to the lines forming the other angle. and so and as was to be shown. Reflect: As As When (flat surface), This corresponds to the reflected rays traveling in nearly the same direction. All of these limiting results are sensible. 23.30. Set Up: The mirror in its original position and after being rotated by an angle are shown in Figure 23.30. is the angle through which the reflected ray rotates when the mirror rotates. The two angles labeled are equal and the two angles labeled
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Unformatted text preview: are equal because of the law of reflection. The two angles labeled are equal because the lines forming one angle are perpendicular to the lines forming the other angle. Figure 23.30 Solve: From the diagram, and as was to be shown. a 5 2 u , u 5 f r 2 f . a 5 2 f r 2 2 f 5 2 1 f r 2 f 2 f f f9 f9 u a Incident ray Normal to mirror Ray reflected from mirror Normal to rotated mirror Mirror Ray reflected from rotated mirror Rotated mirror u f r f a u u S 360°. A S 180° u S 180°. A S 90°, u S 0°. A S 0°, u 5 2 A , u 2 5 b 1 g 5 A 2 1 A 2 5 A . b 5 A 2 . a 5 b b 1 f 5 90°, a 1 f 5 90° a 5 A 2 g 5 A 2 b g f f a A 2 u 2 u 2 u . f 23-8 Chapter 23...
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• Spring '07
• Shoberg
• 0°, 1 g, 90°, 2 g, 5 90°

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