23_InstSolManual_PDF_Part12

23_InstSolManual_PDF_Part12 - 42.5 5 1.48. n liq sin 42.5 5...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
(b) water to air: As Figure 23.44 shows, and Figure 23.44 23.45. Set Up: The light is in diamond and encounters an interface with air, so and The largest is when Solve: and 23.46. Set Up: The critical angle occurs when light in liquid encounters an interface with air. When Solve: (a) First solve for Then with and gives and (b) Now and and u b 5 22.8°. sin u b 5 1 n a n b 2 sin u a 5 1 1.00 2 sin 35.0° 1.48 5 0.3876 u a 5 35.0°. n b 5 1.48 n a 5 1.00, u b 5 58.1°. sin u b 5 1 n a n b 2 sin u a 5 1 1.48 2 sin 35.0° 1.00 5 0.849 u a 5 35.0° n b 5 1.00 n a 5 1.48, n a sin u a 5 n b sin u b n liq 5 n air sin 90° sin 42.5° 5 1 sin
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 42.5 5 1.48. n liq sin 42.5 5 n air sin 90. n liq : n a sin u a 5 n b sin u b . u b 5 90. u a 5 42.5, n b 5 n air . n a 5 n liq , u a 5 24.4. sin u a 5 1 2.42 1 2.42 2 sin u a 5 1 1.00 2 sin 90. u b 5 90. u a n b 5 1.00. n a 5 2.42 n a sin u a 5 n b sin u b . 48 48 65 25 Air Water X sin u b 5 1 n a n b 2 sin u a 5 1 1.333 2 sin 48 5 82. n b 5 1.00. n a 5 1.333 u a 5 48. 23-12 Chapter 23...
View Full Document

This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

Ask a homework question - tutors are online