23_InstSolManual_PDF_Part20 - 2 1 1.0 3 10 2 W m 2 2 1 8.85...

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(b) (c) The pressure is so (d) The intensity of this laser is much less than what is needed to sup- port a sheet of paper. And to support the paper, not only must the intensity be large, it also must be over a large area. 23.77. Set Up: Solve: (a) (b) (c) (d) 23.78. Set Up: The angle of incidence at A is to be the critical angle. The ray is sketched in Figure 23.78. Figure 23.78 Solve: For glass air at point A , Snell’s law gives and Snell’s law applied to the refraction from air to glass at the top of the block gives and u a 5 72.1°. 1 1.00 2 sin u a 5 1 1.38 2 sin 1 43.6° 2 90° 2 u crit 5 43.6°. u b 5 u crit 5 46.4°. 1 1.38 2 sin u crit 5 1 1.00 2 sin 90° S u a u b u crit A I 5 1 1.0 3 10 2 W / m 2 2 1 1 m 10 2 cm 2 2 5 0.010 W / cm 2 P 5 0.18 mW 5 0.18 mJ / s B max 5 E max c 5 9.13 3 10 2 7 T E 5 Å 2 I P 0 c 5 Å 2
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Unformatted text preview: 2 1 1.0 3 10 2 W / m 2 2 1 8.85 3 10 2 12 C 2 / N # m 2 21 3.00 3 10 8 m / s 2 5 274 V / m. P 5 IA 5 1 1.0 3 10 2 W / m 2 2 p 1 0.75 3 10 2 3 m 2 2 5 1.8 3 10 2 4 W 5 0.18 mW E max 5 cB max . I 5 1 2 P cE max 2 . I 5 P A . I 5 P A 5 0.500 3 10 2 3 W p 1 0.500 3 10 2 3 m 2 2 5 637 W / m 2 . I 5 mgc 2 A 5 3.58 3 10 7 W / m 2 . 1 2 I c 2 A 5 mg . 2 I c B max 5 E max c 5 2.32 3 10 5 V / m 3.00 3 10 8 m / s 5 7.74 3 10 2 4 T. E max 5 Å 2 I P c 5 Å 2 1 7.16 3 10 7 W / m 2 2 1 8.85 3 10 2 12 C 2 / N # m 2 21 3.00 3 10 8 m / s 2 5 2.32 3 10 5 V / m. I 5 1 2 P cE max 2 . 23-20 Chapter 23...
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